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3 years ago

Mass = 325.2 volume = 62.5 cm what's the density ?

Chemistry

2 answers:

Eduardwww [97]3 years ago

6 0

Answer:

the required density = 5.2

Explanation:

density = mass / volume, so

density = 325.2 / 62.5 = 5.2

boyakko [2]3 years ago

3 0

Answer:

159571 lb or cubic feet

Explanation:

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Find the enthalpy of neutralization of HCl and NaOH. 137 cm3 of 2.6 mol dm-3 hydrochloric acid was neutralized by 137 cm3 of 2.6

liraira [26]

Answer : The correct option is, (D) 89.39 KJ/mole

Explanation :

First we have to calculate the moles of HCl and NaOH.

$\text{Moles of HCl}=\text{Concentration of HCl}\times \text{Volume of solution}=2.6mole/L\times 0.137L=0.3562mole$

$\text{Moles of NaOH}=\text{Concentration of NaOH}\times \text{Volume of solution}=2.6mole/L\times 0.137L=0.3562mole$

The balanced chemical reaction will be,

$HCl+NaOH\rightarrow NaCl+H_2O$

From the balanced reaction we conclude that,

As, 1 mole of HCl neutralizes by 1 mole of NaOH

So, 0.3562 mole of HCl neutralizes by 0.3562 mole of NaOH

Thus, the number of neutralized moles = 0.3562 mole

Now we have to calculate the mass of water.

As we know that the density of water is 1 g/ml. So, the mass of water will be:

The volume of water = $137ml+137ml=274ml$

$\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1g/ml\times 274ml=274g$

Now we have to calculate the heat absorbed during the reaction.

$q=m\times c\times (T_{final}-T_{initial})$

where,

q = heat absorbed = ?

$c$ = specific heat of water = $4.18J/g^oC$

m = mass of water = 274 g

$T_{final}$ = final temperature of water = 325.8 K

$T_{initial}$ = initial temperature of metal = 298 K

Now put all the given values in the above formula, we get:

$q=274g\times 4.18J/g^oC\times (325.8-298)K$

$q=31839.896J=31.84KJ$

Thus, the heat released during the neutralization = -31.84 KJ

Now we have to calculate the enthalpy of neutralization.

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = enthalpy of neutralization = ?

q = heat released = -31.84 KJ

n = number of moles used in neutralization = 0.3562 mole

$\Delta H=\frac{-31.84KJ}{0.3562mole}=-89.39KJ/mole$

The negative sign indicate the heat released during the reaction.

Therefore, the enthalpy of neutralization is, 89.39 KJ/mole

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4 years ago

Find the molar mass of 2Cu (NO3)2

8090 [49]

Answer:

187.5558 mol

Explanation:

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3 years ago

Give three examples, from the lab, where potential energy was converted to kinetic energy.

GREYUIT [131]

Give 3 Examples of where potential energy was converted to knlinetic energy:

Curtain

A ball before moving

An apple from the tree then falling down

When the Curtains are still, we call the that potential energy. If you move the curtains around, that is kinetic energy

The ball is still, that is potential energy. Then the ball is moving, the is kinetic energy

There is a apple ganging from a tree, that is potential energy. That apple is fall, this is kinetic energy

Hope this helps

Don't type or write in the answer, I'm not sure what from the lab means. These are a few potential into kinetic energy I could have think of!

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3 years ago

Which compounds were classified as organic compounds according to the early chemists

Alona [7]

Answer:

Organic compound, any of a large class of chemical compounds in which one or more atoms of carbon are covalently linked to atoms of other elements, most commonly hydrogen, oxygen, or nitrogen.

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3 years ago

Calculate the quantity of energy required to change 8.22 mol of liquid water to steam at 100oc. the molar heat of vaporization o

Ainat [17]

Since the water is at 100 degrees then it take 40.6 kj/mol to change 1 mole of water at 100 degrees into steam at 100 degrees
the moles of water 8.22mol
since one mole take 40.6kj/mol 8.22mol will be =
8.22mol x 40.6 kj/mol =333.732 kj

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3 years ago