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scoundrel [369]
1 year ago
11

What does it mean to be in the path of totality?

Chemistry
1 answer:
inysia [295]1 year ago
4 0

Answer:

The track of the Moon's shadow across Earth's surface

Explanation:

<h3>hope this help you </h3>
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What is the pOH of a 0.025 M [H+] solution? A.0.94 B.1.60 C.12.40 D.13.06
Greeley [361]

Answer:

option C= 12.40

Explanation:

Formula:

pH + pOH = 14

First of all we will calculate the pH.

pH = - log [H⁺]

pH = - log [0.025]

pH = - (-1.6)

pH = 1.6

Now we will put the values in formula,

pH + pOH = 14

pOH = 14-pH

pOH = 14 -1.6

pOH = 12.4

The pOH of solution is 12.4.

6 0
2 years ago
How does e=mc^2 connect to quarks
Jobisdone [24]

Answer:

good bro

Explanation:

5 0
2 years ago
Which particles have a similar relative mass
olganol [36]

Answer:

c ) protons and neutrons

Explanation:

Protons and neutrons have approximately the same mass, but they are both much more massive than electrons (approximately 2,000 times as massive as an electron). The positive charge on a proton is equal in magnitude to the negative charge on an electron.

7 0
3 years ago
Calculate the mass, in grams, of Ag2CrO4 that will precipitate when 50.0mL of 0.20M AgNO3 solution is mixed with 40.0mL of 0.10M
Darina [25.2K]

Answer:

1.327 g Ag₂CrO₄

Explanation:

The reaction that takes place is:

  • 2AgNO₃(aq) + K₂CrO₄(aq)  → Ag₂CrO₄(s) + 2KNO₃(aq)

First we need to <em>identify the limiting reactant</em>:

We have:

  • 0.20 M * 50.0 mL = 10 mmol of AgNO₃
  • 0.10 M * 40.0 mL = 4 mmol of K₂CrO₄

If 4 mmol of K₂CrO₄ were to react completely, it would require (4*2) 8 mmol of AgNO₃. There's more than 8 mmol of AgNO₃ so AgNO₃ is the excess reactant. <em><u>That makes K₂CrO₄ the limiting reactant</u></em>.

Now we <u>calculate the mass of Ag₂CrO₄ formed</u>, using the <em>limiting reactant</em>:

  • 4 mmol K₂CrO₄ * \frac{1mmolAg_2CrO_4}{1mmolK_2CrO_4} *\frac{331.73mg}{1mmolAg_2CrO_4} = 1326.92 mg Ag₂CrO₄
  • 1326.92 mg / 1000 = 1.327 g Ag₂CrO₄
7 0
2 years ago
What is a substance?
ANTONII [103]
A is the answer im pretty sure
5 0
3 years ago
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