List the prime numbers between 50 and 60

Mathematics

1 answer:

katrin2010 [14]3 years ago

7 0

51, 53, 55, 57, 59. it's simple.

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For a particular event, 771 tickets were sold for a total of $3037. If students paid $3 per ticket and non-students paid $5

BlackZzzverrR [31]

Answer:

Number of student tickets were sold = 409

Step-by-step explanation:

Total number of tickets sold = 771

I.e Students ticket (S) + Non students ticket(N S) = 771

Total amount to be paid for tickets = $ 3037

Amount paid by students per tickets = $3

Amount paid by non-students per tickets = $5

So, according to question

S + NS = 771

3 S + 5 NS = 3037

Solve both equations

5 S + 5 NS = 771 × 5

3 S + 5 NS = 3037

so ,

(5 S + 5 NS) - (3 S + 5 NS ) = 3855 - 3037

Or, 2 S = 818

I.e S = $\frac{818}{2}$ = 409

Hence, The number of student tickets were sold = 409 Answer

5 0

3 years ago

Lengths of full-term babies in the US are Normally distributed with a mean length of 20.5 inches and a standard deviation of 0.9

mash [69]

Answer:

66.48% of full-term babies are between 19 and 21 inches long at birth

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean length of 20.5 inches and a standard deviation of 0.90 inches.

This means that $\mu = 20.5, \sigma = 0.9$