The answer for your problem is shown on the picture.
Answer:
Step-by-step explanation:
To evaluate for such, the following comprehension is required,
Equation Required: Distance Formula: d(P, Q) = √ (x2 − x1)^2 + (y2 − y1)^2
Denote the configurations as the following,
(5, -1). (5, -4)
X1 Y1. X2. Y2
D(P, Q) = √(5 - 5)^2 + (-4 +1)^2. <== Since the double negative is present, the operation is acknowledged as positive.
D(P, Q) = √(0)^2 + (-3)^2
D(P, Q) = √9 = 3
Thus, the agglomerate distance between the points situated in the Cartesian plane is disclosed, and is, henceforth, disseminated as 03 units.
Answer:
4 2 8 89 8
Step-by-step explanation:
Answer:
y - x= - 13 -------(1)
- 4x + 3y = -51 -------(2)
(1) => y = - 13 + x
Substitute y in (2)
- 4x + 3( - 13 + x) = -51
- 4x - 39 + 3x = -51
- x = -51 + 39
- x = -12
x = 12
Substitute x in (1)
y = - 13 + x = -13 + 12 = - 1
x = 12, y = -1
