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prisoha [69]
3 years ago
12

find the circumference of the circle shown below. Remember to use 3.14 for LaTeX: \piπ, and be sure to round your final answer t

o the nearest hundredth, as needed.

Mathematics
1 answer:
nevsk [136]3 years ago
7 0

Answer:

62.8   If rounded to the nearest hundredth it is 62.80

Step-by-step explanation:

1.  Formula for circumference of a cirlcle is 2 (pi) r  where for this problem,

2 =2,

pi= 3.14 and

r= 10 (1/2 of the diameter =radius)

2.   2 x 3.14 x 10

multiply all 3 numbers above, you get 62.8

3. Depending on your teacher or the test,

62.8 is your answer, if it HAS to be to the nearest hunderedth, and it's on a specific program, it might want you to enter the "0" at the end   62.80

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Elasticity of Demand The demand function for a certain brand of backpacks is
Trava [24]

Answer:

See explanation

Step-by-step explanation:

Solution:-

- The demand function of a certain brand is given as price P a function of x quantity of goods ( in hundred ) demanded per month. The relation is:

                           P ( x ) = 50 Ln ( 50 / x ).

- The point price elasticity ( E ) of demand is given by:

                           E = \frac{P}{x}*\frac{dP}{dx}  

- Where, dP / dx : is the rate of change of price ( P ) with each hundred unit of good ( x ) is demanded.

- To determine the " dP / dx " by taking the first derivative of the given relation:

                          P ( x ) = 50 Ln ( 50 / x ).

                          d P ( x ) / dx = [ 50*x / 50 ] * [ -1*50 / x^2 ]

                                              = - 50 / x

- Hence the point price elasticity of demand is given by:

                          E = - ( P / x ) * ( 50 / x )

                          E = -50*P / x^2    

- For an inelastic demand, ! E ! is < 1:

                          ! -50*P / x^2 ! < 1

                          50*P / x^2 < 1

                          P < x^2 / 50

- For an unitary demand, ! E ! is =  1:

                          ! -50*P / x^2 !  = 1

                          50*P / x^2 = 1

                          P = x^2 / 50

- For an inelastic demand, ! E ! is > 1:

                          ! -50*P / x^2 ! > 1

                          50*P / x^2 > 1

                          P > x^2 / 50

2)

If the unit price is increased slightly from $50, will the revenue increase or decrease?

- We see from the calculated demand sensitivity d P / dt:

                          d P ( x ) / dx = - 50 / x

- We see that as P increases the from P = $50, the quantity of goods demanded would be:

                          50 = 50 ln(50/x)

                           1 = Ln ( 50 / x )

                           50/x = e

                           x = 50 / e

Then,

                          d P ( x ) / dx = - 50 / ( 50 / e )

                          d P ( x ) / dx = - e

- We see that if price slightly increases from $ 50 then the quantity demanded would decrease by e (hundreds ) goods.

- The decrease in the quantity demanded is higher than the increase in price. The revenue is given by the product of price P ( x ) and x:

                Revenue R ( x ) = P ( x ) * x

                                = 50*x*ln(50/x)

Then the product of price and quantity goods also decreases; hence, revenue decreases.

8 0
3 years ago
If f(x)=4(3x-5), find f^-1(x)
Margaret [11]

Answer:

f^-1(x) = (x+20) / 12

Step-by-step explanation:

f(x) = 4(3x-5)

Let y be the image of f.

y = 4(3x-5)

y = 12x-20

y+20 = 12x

x = (y+20) / 12

f^-1(y) = (y+20) / 12, so

f^-1(x) = (x+20) / 12

3 0
2 years ago
Refer the homework helper what is the diffrence between the greatest green bean weight and the least green bean weight?
QveST [7]

Answer:

3/4 pounds

Step-by-step explanation:

Given the weights :

weight of beans 1/4 pound, 1/2 pound, 3/4. pound and 1 pound.​

Greatest weight = 1 pound

Least weight = 1/4 pound

Difference = greatest weight - Least weight

Difference = (1 - 1/4) pound

Difference in weight = 3/4 pounds

6 0
3 years ago
Please help me asap!
Mazyrski [523]

Answer:

x value is 10 as per as the question its value is 10

3 0
3 years ago
Suppose f varies directly as g, and f varies inversely as h. Find g when f = 12 and h = 10, if g = 198 when h = –11 and f = –6.
sattari [20]

Answer:

360

Step-by-step explanation:

f varies directly as g

f = kg  where k is the constant of variation

f varies inversely as h

f = kg/h

We know g = 198 when  h = –11 and f = –6.  Substituting in

-6 = k*198/(-11)

-6 =k*(-18)

Dividing each side by -18

-6/-18 = k*-18/-18

1/3 =k

Our equation is

f = 1/3 g/h

Letting  f = 12 and h = 10

12 = 1/3 g/10

Multiply each side by 10

12*10 =1/3 g/10*10

120 = 1/3 g

Multiply each side by 3

120*3 =1/3 g *3

360 =g

5 0
3 years ago
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