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3 years ago

What is the equation of the circle shown below?

Mathematics

1 answer:

Kitty [74]3 years ago

7 0

Answer:

( x+2)^2 + ( y+2) ^2 = 9

Step-by-step explanation:

The center is at (-2,-2)

The radius is 3 which is the number of units from the center to the circles edge

The equation of a circle can be written as

( x-h) ^2 + (y-k) ^2 = r^2 where ( h,k) is the center and r is the radius

( x--2) ^2 + (y--2) ^2 = 3^2

( x+2)^2 + ( y+2) ^2 = 9

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

Given sin theta= 6/11 and sec theta < 0, find cos theta and tan theta.

bekas [8.4K]

Answer: option a.

Step-by-step explanation:

By definition, we know that:

$cos^2(\theta)=1-sen^2(\theta)\\\\tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

Substitute $sin(\theta)=\frac{6}{11}$ into the first equation, solve for the cosine and simplify. Then, you obtain:

$cos(\theta)=\±\sqrt{1-(\frac{6}{11})^2}\\\\cos(\theta)=\±\sqrt{\frac{85}{121}}\\\\ cos(\theta)=\±\frac{\sqrt{85}}{11}$

As $sec\theta$ then $cos\theta$ :

$cos(\theta)=-\frac{\sqrt{85}}{11}$

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$tan\theta=\frac{\frac{6}{11}}{-\frac{\sqrt{85}}{11}}\\\\tan\theta=-\frac{6\sqrt{85}}{85}$

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3 years ago

Read 2 more answers