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aksik [14]
3 years ago
6

Helpppppppppppppp I’ll mark u

Mathematics
1 answer:
Nataly_w [17]3 years ago
4 0
-35 is the answer hope this helps
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Solve.<br> x<br> __<br> 2 = 7<br> ----------------------------------------<br> PLEASE HELP!
galina1969 [7]
\frac{x}{2} = 7\\\\\frac{x}{2} \times 2 = 7\times2\\\\\boxed{x=14}
5 0
4 years ago
3y(2y+5) solve the problem
pochemuha

3y×(2y+5)

Multiply each term in the parentheses by 3y

3y×2y+3y×5

Calculate the product

6y²+3y×5

Now we do the same thing only different way

3y×2y

Multiply the numbers

6y×y

If  a term doesn't have an exponent , it is considered that the exponent is 1

6y^1×y^1

Multiply the terms with the same base by adding their exponents

6y^1+1

add the numbers

6y²

6y^2+3y×5×

calculate the product

6y²+15y

It's the same thing only different way ok

3y×5

Multiply the numbers

15y

answer: 6y²+15y

PLEASE MARK ME AS BRAINLIEST

6 0
3 years ago
Solve for x- round to the nearest tenth- Trigonometry
Rashid [163]

Answer:

sin26=11/X

0.438371146789×x=11

X. = 11/0.438371146789

X=25.09289235975

4 0
3 years ago
The exponential model A=429e 0.024t describes the​ population, A, of a country in​ millions, t years after 2003. Use the model t
d1i1m1o1n [39]

Answer:

Year 2,590

Step-by-step explanation:

In this question, we are asked to calculate the year at which the population of a country will be a certain amount given the exponential equation through which the equation proceeds.

Let’s rewrite the exponential function;

A = 429e^0.024t

Now here, our A is 559,000,000

t is unknown

Let’s substitute this value of A in the exponential equation;

559,000,000 = 429 * e^0.024t

559,000,000/429 = e^0.024t

1,303,030.303030303 = e^0.024t

Let’s take the logarithm of both sides to base e, we have;

ln(1,303,030.303030303) = ln(e^0.024t)

14.08 = 0.024t

t = 14.08/0.024

t = 587 years

Now, we add this to year 2003 and this gives year 2590

7 0
4 years ago
5/6 of 15 i need help????????????
emmainna [20.7K]

Answer: 12.5 or 12 1/2

Step-by-step explanation:

7 0
3 years ago
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