Answer:
50%
Step-by-step explanation:
The P(even or divisor of 28) = P(even) + P(divisor of 28) - P(even and divisor of 28). The P(even) = 2/4 = 1/2. The P(divisor of 28) = 2/4 = 1/2. The P(even and divisor of 28) = 2/4 = 1/2 as 2,4 are even numbers and divisors of 28.
1/2 + 1/2 - 1/2 = 1/2 = 50%
Let h = the number of horses in the field
Let c = number of cows in the field
There are 2 more horses than cows in the field. Therefore
h = c + 2
or
c = h - 2 (1)
There are 15 animals in the field. Therefore
h + c = 15 (2)
Substitute (1) into (2).
h + (h - 2) = 15
2h - 2 = 15
Answer:
The correct equation is
2h - 2 = 15
The area of the circle should be 201.06
Answer:
x = 6
Step-by-step explanation:
7 x = 56-14
7 x = 42
7 x/7 to remain with x only = 42
then x = 6
Answer:
The sweat chloride reference value is less than 30 mmol/L. A value of more than 60 mmol/L of chloride in the sweat is consistent with a diagnosis of cystic fibrosis. The values of 30-60 mEq/L may represent heterozygous carriers, these carriers cannot be accurately identified with a sweat chloride test.
