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Vedmedyk [2.9K]
3 years ago
7

What is the slope of a line that goes through the points 1,-5 and -3,2? I'm helping my niece

Mathematics
1 answer:
a_sh-v [17]3 years ago
4 0
M = (y2 - y1)/(x2-x1)
 = 2+5/-3-1
 = 7/-4
 = -7/4
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Scores on a dental anxiety scale range from 0​ (no anxiety) to 20​ (extreme anxiety). The scores are normally distributed with a
solniwko [45]

Answer:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

Step-by-step explanation:

The following information is missing in the question:

We have to find z-score for the given score on this dental anxiety scale: 12, 6

We are given the following information in the question:

Mean, μ = 11

Standard Deviation, σ = 4

We are given that the distribution of score is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

where x is the given score on this dental anxiety scale.

For x = 12

z_{score} = \displaystyle\frac{12-11}{4} = 0.25

For x = 6

z_{score} = \displaystyle\frac{6-11}{4} = -1.25

6 0
3 years ago
Translate “the perimeter of a rectangle is equal to 2 times the length plus twice the width
EastWind [94]
Perimeter (p)= 2l+2w
3 0
3 years ago
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What day of the week will March 5th 3555 be?
Novay_Z [31]
It will be a saturday
4 0
3 years ago
Consider the graph of the quadratic function y = 3x2 – 3x – 6. What are the solutions of the quadratic equation 0 = 3x2 − 3x − 6
son4ous [18]
Y = 3x^2 - 3x - 6 {the x^2 (x squared) makes it a quadratic formula, and I'm assuming this is what you meant...}

This is derived from:
y = ax^2 + bx + c

So, by using the 'sum and product' rule:

a × c = 3 × (-6) = -18

b = -3

Now, we find the 'sum' and the 'product' of these two numbers, where b is the 'sum' and a × c is the 'product':

The two numbers are: -6 and 3

Proof:

-6 × 3 = -18 {product}

-6 + 3 = -3 {sum}

Now, since a > 1, we divide a from the results

-6/a = -6/3 = -2

3/a = 3/3 = 1

We then implement these numbers into our equation:

(x - 2) × (x + 1) = 0 {derived from 3x^2 - 3x - 6 = 0}

To find x, we make x the subject of 0:

x - 2 = 0

OR

x + 1 = 0

Therefore:

x = 2

OR

x = -1

So the x-intercepts of the quadratic formula (or solutions to equation 3x^2 - 3x -6 = 0, to put it into your words) are 2 and -1.


We can check this by substituting the values for x:

Let's start with x = 2:

y = 3(2)^2 - 3(2) - 6
= 3(4) - 6 - 6
= 12 - 6 - 6
= 0 {so when x = 2, y = 0, which is correct}

For when x = -1:

y = 3(-1)^2 - 3(-1) - 6
= 3(1) + 3 - 6
= 3 + 3 - 6
= 0 {so when x = -1, y = 0, which is correct}
7 0
3 years ago
Read 2 more answers
<
Sergio [31]

\qquad \qquad  \bf \huge\star \:  \:  \large{  \underline{Answer} }  \huge \:  \: \star

  • Angle x = 29°

\textsf{  \underline{\underline{Steps to solve the problem} }:}

  • \sf \: \angle x + 109 + 42  = 180

( makes co - interior angles, since the two lines are parallel )

  • \sf \:  \angle \: x + 151 = 180

  • \sf \:  \angle x =18 0 - 151

  • \sf \: \angle x = 29 \degree

\qquad \large \sf {Conclusion}  :

  • x = 29°

4 0
1 year ago
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