Answer:
B. 0.42
Explanation:
Since the two alleles are at Hardy-Weinberg equilibrium, the sum of the frequency of two alleles will be one. If the frequency of a dominant allele is "p" and that of the recessive allele is "q", then p+q=1
According to the given information, the frequency of one allele in the population is= 0.7
This means that the frequency of the other allele would be= 1-0.7 = 0.3
Frequency of heterozygote in the population =2pq = 2 x 0.7 x 0.3 = 0.42
2. Process to test hypotheses
Answer:
The frequency of the recessive allele. Answer: Since we believe that the homozygous recessive for this gene (q2) represents 4% (i.e. = 0.04), the square root (q) is 0.2 (20%).
The frequency of the dominant allele. Answer: Since q = 0.2, and p + q = 1, then p = 0.8 (80%).
The frequency of heterozygous individuals.
Explanation:
Answer:
B
Explanation:
A zygote is the resulting cell from fertilization.
Fertilization occurs when the sperm (the male gamete/sex cell) fuses with the egg (the female gamete/sex cell). After they fuse, or fertilize, a cell forms that contains half of the DNA from the father (sperm) and the other half from the mother (egg). It has a complete set of DNA, and is considered a haploid cell.
It is not the structure that nourishes the fetus, an un-fertilized egg, or a ball of about 100 cells. Therefore, the correct answer is <u>B: a sperm fused with an egg.</u>
