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2 years ago

Complete the table of values for the linear relation y = -5x + 10.

Mathematics

1 answer:

musickatia [10]2 years ago

3 0

the answer will be -5

Step-by-step explanation:

because you have to minus 5 and 10

so the answer will be x =- 5

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PLEASE HELP I WILL GIVE BRAINLEST AND 20 POINTS PLEASEEEE

rewona [7]

Answer:

Question 4: Which equation is parallel to the above equation and passes through the point (35, 30)

$y=$ $\frac{5}{7} x + 5$ is the correct answer, I found this by inputting the x and y value of the coordinate (35, 30) onto the equation and solving for y-intercept since the slope of all equations is the same (since it's traveling parallel)

$30 = \frac{5}{7} (35) + y\\30 = 25 + y\\5 = y$

so the equation would be $y=$ $\frac{5}{7} x + 5$

Question 5: Which equation is perpendicular to the above equation and passes through the point (35, 30)

$y=\frac{-7}{5} x+79$ is the correct answer, I found this using the same method as before, input coordinate values into the equation and solve for the y-intercept (The only thing changed from the last answer is the opposite reciprocal slope).

$30 = \frac{-7}{5}(35) + y \\30 = -49 + y \\79 = y$

so the equation would be $y=\frac{-7}{5} x+79$

6 0

2 years ago

Find the length of FT¯¯¯¯¯¯¯ A. 77.71 B. 72.47 C. 56.84 D. 49.42

Mkey [24]

Answer:

D, 49.42

Step-by-step explanation:

ΔVFT=180-90-43=47

formula

a/sin A = b/sin B/ = c/sin C

So,

FV/sin90=53/sin47

FV=72.4684

FT=√(72.4684)^2-(53)^2

FT=49.4234

Ans:D

5 0

3 years ago

Read 2 more answers

Find the value of cos 0 , If sec 0 = 3/2 0 < 90

UNO [17]

Answer:

Step-by-step explanation:

cos theta is 2/3 because cos means reciprocal of sec

7 0

2 years ago

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Please help me, just need the answer and thank you!

Triss [41]

Answer to what? I’m confused lol

6 0

3 years ago

Read 2 more answers

Please please help me

Gekata [30.6K]

Answer:

$\large\boxed{\dfrac{\boxed{8}}{81}}$

Step-by-step explanation:

$\text{If}\ a_1,\ a_2,\ a_3,\ a_4,\ ...,\ a_n\ \text{is the geometric sequence, then}\\\\\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}=\dfrac{a_4}{a_3}=...=\dfrac{a_n}{a_{n-1}}=constant=r-\text{common ration}.\\\\\text{We have}\ \dfrac{1}{2},\ \dfrac{1}{3},\ \dfrac{2}{9},\ \dfrac{4}{27},\ ...\\\\\dfrac{\frac{1}{3}}{\frac{1}{2}}=\dfrac{1}{3}\cdot\dfrac{2}{1}=\dfrac{2}{3}\\\\\dfrac{\frac{2}{9}}{\frac{1}{3}}=\dfrac{2}{9}\cdot\dfrac{3}{1}=\dfrac{2}{3}\\\\\dfrac{\frac{4}{27}}{\frac{2}{9}}=\dfrac{4}{27}\cdot\dfrac{9}{2}=\dfrac{2}{3}$

$\bold{CORRECT}\\\\\dfrac{x}{\frac{4}{27}}=\dfrac{2}{3}\qquad\text{multiply both sides by}\ \dfrac{4}{27}\\\\x=\dfrac{2}{3}\cdot\dfrac{4}{27}\\\\x=\dfrac{8}{81}$

8 0

3 years ago