Try C if it doesn’t work try A,B,D
Answer:
1x0
2 x 11
1x0
Hope this helps! :) Please rate brainliest
The standard equation is y=ax^2+bx+k and the vertex way is y=a(x-h)(x-h)+x
so the coordinate for x is -b/2a, for your problem a=-4 b=-16 so the coordinate for x is -(-16)/(2*(-4))=-2. Now you have to replace x=-2 in your equation y=-4(-2)^2-16(-2)-11= 5.
The vertex is (-2, 5)
Probally d most likely because if you know what the deer looks like it is orange and white spots so it is more manipulating the light from the leaves. If im wrong then its A
Answer:
x(t) = - 5 + 6t and y(t) = 3 - 9t
Step-by-step explanation:
We have to identify the set of parametric equations over the interval 0 ≤ t ≤ 1 defines the line segment with initial point (-5,3) and terminal point (1,-6).
Now, put t = 0 in the sets of parametric equations in the options so that the x value is - 5 and the y-value is 3.
x(t) = - 5 + t and y(t) = 3 - 6t and
x(t) = - 5 + 6t and y(t) = 3 - 9t
Both of the above sets of equations satisfy this above conditions.
Now, put t = 1 in both the above sets of parametric equations and check where we get x = 1 and y = -6.
So, the only set, x(t) = - 5 + 6t and y(t) = 3 - 9t satisfies this condition.
Therefore, this is the answer. (Answer)