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bija089 [108]
3 years ago
15

Knowing that P = X x i / 100, C = main, e = Rate. Calculate the rate for the formula: A principal of R $ 105,000.00 obtained a p

ercentage of R $ 35,000.00. What is the rate applied?
Mathematics
1 answer:
Brut [27]3 years ago
3 0

Answer:

Interest expressed as a percent of the principal will be referred to as an ... earned on an investment of P at the annual interest rate r for a period of t ... (c) monthly, (​d) weekly, (e) daily, and (f) continuously at a nominal annual ... and substitute x = 3−2y in for x in second equation and find 4y−3(3−2y) = 1.

Step-by-step explanation: sorry if that doesn't help :(

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Answer:

\boxed{5 \cdot \sqrt{2}  \cdot \sqrt[6]{5} }

Step-by-step explanation:

\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }

\sqrt{\sqrt[3]{10} } \implies (10^\frac{1}{3} )^\frac{1}{2} =10^\frac{1}{6} =\sqrt[6]{10}

\therefore \sqrt{\sqrt[3]{10} }=\sqrt[6]{10}

\text{Solving }\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }

250=2 \cdot 5^3

\sqrt[3]{250}=\sqrt[3]{2\cdot 5^3}=5  \sqrt[3]{2}

Once

\sqrt[6]{2}  \cdot \sqrt[6]{5} = \sqrt[6]{10}

We have

5  \sqrt[3]{2} \cdot \sqrt[6]{2}  \cdot \sqrt[6]{5}

We can proceed considering the common base of exponentials

\sqrt[3]{2}  \cdot \sqrt[6]{2}  =  2^{\frac{1}{3}} \cdot  2^{\frac{1}{6} }  = 2^{\frac{3}{6} } = 2^{\frac{1}{2} }=\sqrt{2}

Therefore,

5  \sqrt[3]{2} \cdot \sqrt[6]{2}  \cdot \sqrt[6]{5} = 5 \cdot \sqrt{2}  \cdot \sqrt[6]{5}

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