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3 years ago

6

a glider is gliding through the air at a height of 416 meters with s speed of 45.2 m/s. The glider dives to a height of 278 mete

rs. Determine the gliders new speed.

1 answer:

grigory [225]3 years ago

4 0

<span>KE+PE=KE+PE is the answer

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Whích graph is generated by this table of values?

arlik [135]

Answer:

23132as

Step-by-step explanation:

kasjdjjaskdsksdjdj

4 0

2 years ago

D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x

MA_775_DIABLO [31]

The solution depends on the value of $k$ . To make things simple, assume $k>0$ . The homogeneous part of the equation is

$\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0$

and has characteristic equation

$r^2-16k=0\implies r=\pm4\sqrt k$

which admits the characteristic solution $y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}$ .

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be $y_p=ae^{4x}+be^x$ . Then

$\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x$

So you have

$16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x$
$(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x$

This means

$16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}$
$b(1-16k)=30\implies b=\dfrac{30}{1-16k}$

and so the general solution would be

$y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x$

8 0

2 years ago

Suppose that the manager of a company has estimated the probability of a super-event sometime during the next five years that wi

daser333 [38]

Answer:

The answer is d) 0.2303%

6 0

3 years ago

Find the value of X so that this quadrilateral is a parallelogram. Then substitute the value of X and using the parallelogram an

Bogdan [553]

Answer:

x = 36

m/A = 132

m/B = 48

m/C = 48

m/D = 132

4 0

3 years ago

Trina's science club is building bluebird houses to put in the local park. For the first 1/6 dozen bird houses, Trina finds that

meriva

<u>Answer:</u>

4.5 foot is needed for a unit dozen bird house

<u>Explanation:</u>

Given Tina saw ¾ foot of wooden trim is being used for first 1/6 dozen bird houses

Therefore, we can write as,4

1/6 dozen = ¾ foot

For 1 dozen bird houses, we have to use the unitary method

1/6 dozen = ¾ foot

Therefore, 1 dozen or unit dozen = $\frac{\frac{3}{4}}{\frac{1}{6}}$

1 dozen = ¾ * 6 = $\frac{9}{2}$ foot = 4.5 foot

Therefore, 4.5 foot is needed for a unit dozen bird house

3 0

3 years ago