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dexar [7]
4 years ago
10

What is binomil (2a–1)(a–3)

Mathematics
2 answers:
Novosadov [1.4K]4 years ago
5 0

Answer:

2a^2-5a+3

Step-by-step explanation:

2a(a-3)-1(a-3)=

2a^2-6a-a+3=

2a^2-5a+3

nevsk [136]4 years ago
3 0

Answer:

Step-by-step explanation:

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Simplify the expression x^2+x-2/8x^2+4x/3x^2+10x+8
irina [24]

Answer:

Step-by-step explanation:

x² + x  - 2 = x² - x +2x -2 = x(x - 1) + 2*(x-1)  = (x-1)(x+2)

8x² + 4x = 4x ( 2x + 1)

3x² + 10x + 8 = 3x² + 6x + 4x + 4*2  =3x  * (x + 2) + 4 * ( x + 2) = (x + 2)(3x + 4)

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3 years ago
What is the mean and median of 73 45 88 90 90 81 83
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Answer:

Mean = 78.5

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4 years ago
Suppose a random variable, x, follows a Poisson distribution. Let μ = 2.5 every minute, find the P(X ≥ 125) over an hour. Round
Mashutka [201]

Answer:

P(X ≥ 125) = 0.9812

Step-by-step explanation:

To solve this question, we need to understand the Poisson distribution and the normal distribution.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\lambda}*\lambda^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\lambda is the mean in the given interval, which is the same as the variance.

Normal distribution:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The Poisson can be approximated to the normal, with \mu = \lambda, \sigma = \sqrt{\lambda}

Let μ = 2.5 every minute

This is the mean of the Poisson, so \lambda = 2.5n, in which n is the number of minutes.

P(X ≥ 125) over an hour

An hour has 60 minutes, so n = 60, \lambda = 2.5*60 = 150, \sigma = \sqrt{150} = 12.25

Using continuity correction, this is P(X \geq 125 - 0.5) = P(X \geq 124.5), which is 1 subtracted by the pvalue of Z when X = 124.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{124.5 - 150}{12.25}

Z = -2.08

Z = -2.08 has a pvalue of 0.0188

1 - 0.0188 = 0.9812

So

P(X ≥ 125) = 0.9812

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