Find sin(a) in the triangle. Choose 1 answer:
1 answer:
Answer:
5/13
Step-by-step explanation:
Find the diagram to the question attached
Given the following considering angle A
Hypotenuse = 13 = AB
Opposite = 5 (side facing the angle A) = BC
Adjacent = 12
According to SOH CAH TOA;
Sin theta = opposite/hypotenuse
Sin(a) = BC/AB
Sin(a) = 5/13
Hence the value of sin(a) is 5/13
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Answer:
ΔABD ≅ ΔACD by SAS, therefore;
by CPCTC
Step-by-step explanation:
The two column proof is presented as follows;
Statement Reason
ABCD is a trapezoid Given
Given
Definition of a trapezoid
ABCD is an isosceles trapezoid Left and right leg are equal
∠BAD ≅ ∠CDA Base angle of an isosceles trapezoid are congruent
Reflexive property
ΔABD ≅ ΔACD By SAS rule of congruency
CPCTC
CPCTC; Congruent Parts of Congruent Triangles are Congruent
SAS; Side Angle Side rule of congruency
The question is incomplete, here is the complete question:
The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.
When will there be less than 1 g remaining?
<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.
<u>Step-by-step explanation:</u>
All radioactive decay processes follow first order reaction.
To calculate the rate constant by given half life of the reaction, we use the equation:
where,
= half life period of the reaction = 46 days
k = rate constant = ?
Putting values in above equation, we get:
The formula used to calculate the time period for a first order reaction follows:
where,
k = rate constant =
t = time period = ? days
a = initial concentration of the reactant = 12.6 g
a - x = concentration of reactant left after time 't' = 1 g
Putting values in above equation, we get:
Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.