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lorasvet [3.4K]

3 years ago

9

Which transformation is not isometric?

2 answers:

rusak2 [61]3 years ago

8 0

A is not isometric since the size of the squares are not the same size

kumpel [21]3 years ago

7 0

D .............................

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Say that every single class in Full Sails Masters Degree in Game Design has a 5% failure rate

natka813 [3]

The monthly failure rate is q = 5% = 0.05
The monthly pass rate is p = 1 - q = 0.95

We want to determine the probability of 12 passes in 12 consecutive months for a student.
P(12 of 12 successes) = ₁₂C₁₂ p¹² q⁰ = 0.95¹² = 0.5404.

Therefore if we have 100 students, the number that gets through 12 consecutive months is
100*005404 = 54 students.

Answer: 54 students are left after 12 months.

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3 years ago

Which equation represents the graphed linear function?

FromTheMoon [43]

Answer:

D y=-1/2x+4

Step-by-step explanation:

use the order parir (4,2) x=4

y=-1/2*4+4

y=-2+4

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3 years ago

Thomas buys tickets for his family to see a movie.

xz_007 [3.2K]

Answer:

1st option?

Step-by-step explanation:

is there more part for the question?

5 0

3 years ago

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The tangents to the curve with equation y = x^3-3x at the points A and B with x coordinates −1 and 4 respectively meet at the po

sladkih [1.3K]

Answer:

$\displaystyle C=\left(\frac{26}{9}, 2\right)$

Step-by-step explanation:

We need to find the equation of the tangent lines of Points A and B.

Differentiate the equation:

$\displaystyle \frac{dy}{dx}=3x^2-3$

Point A has an <em>x-</em>coordinate of -1. Hence, the slope of its tangent line is:

$\displaystyle \frac{dy}{dx}\Big|_{x=-1}=3(-1)^2-3=0$

Find the <em>y-</em>coordinate of Point A using the original equation:

$y(-1)=(-1)^3-3(-1)=2$

Hence, Point A is (-1, 2).

Thus, the tangent line at Point A is:

$y-2=0(x-(-1))$

Simplify:

$y=2$

Point B has an <em>x-</em>coordinate of 4. Hence, the slope of its tangent line is:

$\displaystyle \frac{dy}{dx}\Big|_{x=4}=3(4)^2-3=45$

Find the <em>y-</em>coordinate of Point B:

$y(4)=(4)^3-3(4)=52$

Thus, Point B is at (4, 52).

So, the tangent line at Point B is:

$y-52=45(x-4)$

Simplify:

$y=45x-128$

Point C occurs at the intersections of the tangent lines of Points A and B. Set the two equations equal to each other and solve for <em>x: </em>

$2=45x-128$

We acquire:

$\displaystyle x=\frac{26}{9}$

Since one of our equations is <em>y</em> = 2, the <em>y-</em>coordinate is 2.

Hence, Point C is:

$\displaystyle C=\left(\frac{26}{9}, 2\right)$

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3 years ago

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The scatter plot below represents the weight of a box of cookies based on the number of cookies in the box. A trend line shows t

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I think the statement is true

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3 years ago