Answer:
I'm assuming we're solving for the hypotenuse, which is 21.5
Step-by-step explanation:
If a^2+b^2=c^2
Then 19^2+10^2 =461
This is c^2 so we must find the square root of 461
the square root of 461 is 21.47, or 21.5 rounded to the nearest tenth
4.7244m
convert feet to inches using 1 foot = 12 inches
15.5 feet = 15.5 × 12 = 186 inches
multiply this by 2.54 to convert to cm
186 inches = 186 × 2.54 = 472.44 cm
now 1m = 100cm
divide 472.44 by 100 to convert to m
472.44 ÷ 100 =4.7244m
You know where the glacier is now, and how far it moves in
one year. The question is asking how close to the sea it will be
after many years.
Step-1 ... you have to find out how many years
Step-2 ... you have to figure out how far it moves in that many years
Step-3 ... you have to figure out where it is after it moves that far
The first time I worked this problem, I left out the most important
step ... READ the problem carefully and make SURE you know
the real question. The first time I worked the problem, I thought
I was done after Step-2.
============================
Step-1: How many years is it from 2010 to 2030 ?
(2030 - 2010) = 20 years .
Step-2: How far will the glacier move in 20 years ?
It moves 0.004 mile in 1 year.
In 20 years, it moves 0.004 mile 20 times
0.004 x 20 = 0.08 mile
Step-3: How far will it be from the sea after all those years ?
In 2010, when we started watching it, it was 6.9 miles
from the sea.
The glacier moves toward the sea.
In 20 years, it will be 0.08 mile closer to the sea.
How close will it be ?
6.9 miles - 0.08 mile = 6.82 miles (if it doesn't melt)
Answer:
Cos Z= 4/5
Step-by-step explanation:
Hope it helps you!
