The 3.1 °F/min rate of change of the temperature and 15 minutes change duration gives the change in temperature as 46.5 °F
<h3>How can the change in temperature be found from the rate of change?</h3>
The rate at which the temperature changed = 3.1 °F/min
The duration of the change in temperature = 15 minutes
The relationship between the change in temperature, the rate of change in temperature and the time can be presented as follows;

Where;
∆T = The required change in temperature
∆t = The duration of the change = 15 minutes
Which gives;
∆T = 3.1°F/min × 15 minutes = 46.5 °F
- The change in temperature, ∆T = 46.5 °F
Learn more about the rate of change of a variable here:
brainly.com/question/10208814
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To evaluate the probability that a randomly selected day will be between 28 and 34 minutes we proceed as follows:
P(28<x<34)
First we evaluate the z-score for the above values:
z=(x-σ)/μ
μ=26.7
σ=5.1
when:
x=28
z=(28-26.7)/5.1
z=0.26
P(z<0.26)=0.6026
when x=34
z=(34-26.7)/5.1
z=1.43
P(z<1.43)=0.9236
hence:
P(28<x<34)=0.9236-0.6026=0.321~32.1%
It is 16.256 because I went to google and found it.... yep that simple.
P(1) = P(0) [exp (rt)]
9,800 = 10,000 (0.98)^1
r = loge<span> (0.98) = ln (0.98) = -0.0202
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<span>P(t) = P(0)[exp(-0.0202t)]</span>