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2 years ago

8

Please help me :)))!!!!!!

1 answer:

astraxan [27]2 years ago

4 0

Answer:

16 × <u><em>X </em></u>+ 3=

Step-by-step explanation:

u will get your answer

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What is the sum of 0 of -1

Ksju [112]

Answer:

Of (multiplication) 0*-1=0, sum (addition) 0+(-1)=-1

Step-by-step explanation:

5 0

2 years ago

Here are four digits 9 4 7 5 use two of these digits to make the largest possible two digit number

tiny-mole [99]

Answer:

97

Step-by-step explanation:

3 0

2 years ago

Find the value for x

harkovskaia [24]

Answer:

x=45

Step-by-step explanation:

add (3x-9)+30+24=180

subtract 30 and 24 from both sides

(3x-9) = 126

+9 on both sides

3x=135

divide by 3 on both sides

x=45

7 0

2 years ago

Please help me on this problem

Anna71 [15]

Answer:

The pairs of integer having two real solution for $ax^{2} -6x+c = 0$ are

$a = -4, c = 5$
$a = 1, c = 6$
$a = 2, c = 3$
$a = 3, c = 3$

Step-by-step explanation:

Given

$ax^{2} -6x+c = 0$

Now we will solve the equation by putting all the 6 pairs so we get the following

$-3x^{2} -6x-5 = 0$ for $a = -3 , c=-5$

$-4x^{2} -6x+5 = 0$ for $a = -4 , c=5$

$1x^{2} -6x+6 = 0$ for $a = 1 , c=6$

$2x^{2} -6x+3 = 0$ for $a = 2 , c=3$

$3x^{2} -6x+3 = 0$ for $a = 3 , c=3$

$5x^{2} -6x+4 = 0$ for $a = 5 , c=4$

The above all are Quadratic equations inn general form $ax^{2} +bx+c=0$

where we have a,b and c constant values

So for a real Solution we must have

$Disciminant , b^{2} -4\timesa\timesc \geq 0$

for $a = -3 , c=-5$ we have

$Discriminant =-24$ which is less than 0 ∴ not a real solution.

for $a = -4 , c=5$ we have

$Discriminant = 116$ which is greater than 0 ∴ a real solution.

for $a = 1 , c=6$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 2 , c=3$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 3 , c=3$ we have

$Discriminant =0$ which is equal to 0 ∴ a real solution.

for $a = 5 , c=4$ we have

$Discriminant =-44$ which is less than 0 ∴ not a real solution.

7 0

3 years ago

The equation of the line that is parallel<br> to 4x+2 and passing through (5,15)

Mila [183]

Answer:

y=4x-5.

Step-by-step explanation:

slop-interception form of the required line is y=kx+b, where k - slop, b - intercept;

1) to find value of k:

if the required line is parallel to the given line, then slop of the given line = slop of the required line, it means k=4 and the required line is y=4x+b;

2) to find the value of 'b':

if to substitute the given coordinates into the equation of the given line, then:

15=4*5+b, b= -5.

3) finally, y=4x-5

8 0

2 years ago