First square both sides
1-3x=(x+3)^2 use foil to unfactor it
1-3x=x^2+6x+9 subtract 1 from both sides
-3x=x^2+6x+8 add 3x to both sides
0=x^2+9x+8
Now that we got it equal to zero you have to factor the new trinomial
0=(x+1)(x+8)
Now since both are being multiplied by each other, if you get 1 of them to equal zero then both equal zero since 0 times anything equals 0.
So your solutions are x=-8 and x=-1
Brainliest my answer if it helps you out?
Answer:
n = 2
Step-by-step explanation:
Expand the brackets.
1/2n - 2 - 3 = 3 - 2n - 3
Add or subtract terms.
1/2n - 5 = -2n
Add 5 and 2n on both sides.
1/2n + 2n = 5
5/2n = 5
Multiply both sides by 2/5.
n = 5 × 2/5
n = 10/5
n = 2
Answer:
12
Step-by-step explanation:
Simplify and divide by 5 because they are divisible by 5. Then continue simplifying. Your answere should be 12.
Answer:
X^2 y
Step-by-step explanation:
So now you can make this x^2 y because the ^3 cancels it out
Answer:
The correct answer is C. The 4th term is 11.
Step-by-step explanation:
Since the next term is one more than twice the previous, we can calculate it by the following expression:
So the second term is:
The third term:
And the fourth term:
The correct answer is C. The 4th term is 11.