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Levart [38]
3 years ago
12

You have a car (2000kg) that is accelerating uphill at 5.5 m/s what was the force (N) applied to the car? Remember (F=ma - mg

Physics
1 answer:
sp2606 [1]3 years ago
5 0

Answer:

<em>The force applied to the car was 30,600 N</em>

Explanation:

According to the second Newton's law, the net force applied to an object of mass m is:

F_n=m.a\qquad\qquad [1]

Where a is the acceleration at which the object moves. The net force can be also calculated as the sum of all forces acting on the body.

We have a car of m=2000 Kg, being accelerated at 5.5 m/s^2 by a force F (unknown) directed upwards.

Considering the force is upwards and the weight of the car (W) is directed downwards, the net force is:

F_n=F-W\qquad\qquad [2]

Being W=m.g

Equating [1] and [2]:

F-W=m.a

Adding W:

F=W+m.a

F=m.g+m.a

F=m(g+a)

Substituting:

F=2000(9.8+5.5)

F=2000(15.3)

F=30,600 N

The force applied to the car was 30,600 N

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1) 26.6 m

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2) 10.7 m

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