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alexira [117]
3 years ago
12

A trinket factory can produce 3000 trinkets per day the. warehouse has a capacity of 50000 trinkets .currently there are 8000 tr

inkets in the warehouse assume that no trinkets are going to be shipped out of the warehouse for a while
Mathematics
1 answer:
nata0808 [166]3 years ago
5 0

Answer:

14 days

Step-by-step explanation:

Since there are already 8000 trinkets in the warehouse, this means that we need to find the number of days it will take for the factory to create 42,000 trinkets which would cause the warehouse to max out it's capacity.

50,000 - 8000 = 42,000 trinkets

Since the factory can produce 3000 trinkets per day, we simply need to divide 42,000 by 3000 to get the number of days before the warehouse is at max capacity

42,000 / 3000 = 14 days

Therefore, it will take 14 days for the warehouse to be filled

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What is the answer to 1 1/3 + (-5/6)
Ainat [17]
The answer is 0.5

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Marjorie’s customers bought 94 bouquets at her flower shop for $14 each. What is the total amount customers paid for the bouquet
Rus_ich [418]

Answer:

1316

Step-by-step explanation:

Take the price per bouquet times the number of customers

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5 0
3 years ago
Solve the following system. x2 + y 2= 25 2x + y = 10 The solution set
anzhelika [568]

Answer: {(5,0), (3,4)}

Step-by-step explanation:

You can apply the Substitution method:

- Solve for y from the second equation.

- Substitute into the first equation and solve for x.

Then:

y=10-2x

x^2+y^2=25\\x^2+(10-2x)^2=25\\

(Remember that: (a\±b)^2=a^2\±2ab+b^2)

x^2+(10^2-2(10)(2x)+(2x)^2)=25\\x^2+100-40x+4x^2=25\\5x^2-40x+75=0\\x^2-8x+15=0\\(x-5)(x-3)=0\\\\x=5\\x=3

Substitute the values obtained into one of the original equation and solve for y:

2(5)+y=10\\10+y=10\\y=0\\\\2(3)+y=10\\6+y=10\\y=4

The solution set is: {(5,0), (3,4)}

8 0
3 years ago
5. Find the sum of the first 35 terms of the arithmetic sequence when a = 5 and d = 4
Elza [17]

Answer:

The sum of the first 35 terms of the arithmetic sequence when a = 5 and d = 4 is 2555.

Step-by-step explanation:

Given:

a = 5

d =  4

To Find :

The sum of first 35 terms of the arithmetic sequence  = ?

Solution:

Step 1 : finding the 35th term

a_n = a_1 +(n-1)d

a_35 = 5 +(35-1)4

a_35 = 5 +(34)4

a_35 = 5 +136

a_35 = 141

Step 2: Finding the sum of first 35 terms

S_n = \frac{n(a_1 +a_n)}{2}

Substituting the values

S_n = \frac{35(5+141)}{2}

S_n = \frac{35(146)}{2}

S_n = \frac{35(146)}{2}

S_n = \frac{5110)}{2}

S_n = 2555

7 0
4 years ago
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