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Tems11 [23]
3 years ago
10

HEEEEEELPPPPPPPPPPPPPPPPPP PLSSSSSSSSSSSSSSSSSSSSS

Mathematics
1 answer:
Elza [17]3 years ago
5 0

Answer:

g(n) = 18 - 4n

Step-by-step explanation:

Given the recursive formula

g(n) = g(n - 1) - 4 with common difference d = - 4 and g(1) = 14

The explicit formula for an arithmetic sequence is

g(n) = g(1) + (n - 1)d , then

g(n) = 14 - 4(n - 1)

       = 14 - 4n + 4

       = 18 - 4n

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How many times smaller is 2 × 10-3 than 4 × 10-2? PLEASE HELP
NNADVOKAT [17]
<h2>The required "option A) 20" is correct.</h2>

Step-by-step explanation:

Let x be the smaller than 4 ×10^{-2}.

To find, the number of times smaller is 2 × 10^{-3} than 4 × 10^{-2} = ?

∴ x = \dfrac{4\times 10^{-2}}{2\times 10^{-3}}

= 2 × 10^{-2} × 10^{3}

Using the identity,

a^{m}=\dfrac{1}{a^{-m}}

= 2 × 10^{-2+3}

Using the identity,

a^{m} \timesa^{n}=a^{m+n}

= 2 × 10^{1}

= 2 × 10

= 20

Thus, the required "option A) 20" is correct.

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Step-by-step explanation:

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