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Mademuasel [1]
3 years ago
13

Help help help :)))))))

Mathematics
2 answers:
saveliy_v [14]3 years ago
8 0

Answer:

✓✓ Area of traingle = 1.2 cm^2 ✓✓

Step-by-step explanation:

Hello mate (◕ᴗ◕✿)

=>> In above traingle, <u>height and hypotenuse are </u><u>given</u>

<u>=</u><u>></u><u> </u><u>height</u><u> </u>= 12 cm

<u>=</u><u>></u><u> </u><u>Hypotenuse</u> = 14 cm

✓✓ <u>Area</u><u> of</u><u> </u><u>traingle </u><u>=</u><u> </u><u>1</u><u>/</u><u>2</u><u>(</u><u>base*</u><u>height</u><u>)</u><u> </u><u>✓</u><u>✓</u>

<u> </u>we need to find base of above traingle

<u>Base </u><u>=</u><u> </u><u>√</u><u>H</u><u>y</u><u>p</u><u>o</u><u>t</u><u>e</u><u>n</u><u>u</u><u>s</u><u> </u><u>-</u><u> </u><u>√</u><u>P</u><u>e</u><u>r</u><u>p</u><u>i</u><u>n</u><u>d</u><u>i</u><u>c</u><u>u</u><u>l</u><u>a</u><u>r</u><u> </u>

Base = √14 - √12

Base = 3.7 - 3.4

Base = 0.2 cm

Now, we can find area of traingle

<u>Area</u><u> of</u><u> traingle</u><u> </u><u>=</u><u> </u><u>1</u><u>/</u><u>2</u><u>(</u><u>Base*</u><u>Height</u><u>)</u>

<u> </u><u> </u><u> </u><u>Area</u><u> of</u><u> traingle</u><u> </u><u>=</u><u> </u><u>1</u><u>/</u><u>2</u><u>(</u><u>0</u><u>.</u><u>2</u><u>*</u><u>1</u><u>2</u><u>)</u>

<u> </u><u> </u><u> </u><u>Area</u><u> of</u><u> traingle</u><u> </u><u>=</u><u> </u><u>6</u><u>*</u><u>0</u><u>.</u><u>2</u>

<u> </u><u> </u><u> </u><u> </u><u>Area</u><u> of</u><u> traingle</u><u> </u><u>=</u><u> </u><u>1</u><u>.</u><u>2</u><u> </u><u>cm^</u><u>2</u>

<u> </u>Hope it helps you mate (. ❛ ᴗ ❛.)

forsale [732]3 years ago
4 0

Answer :

➢ 43.3 cm²

Explanation :

let the missing side be c

a = 12 cm

b = 14 cm

Pythagoras theorem :

➢ a² + c² = b²

➢ 12² + c² = 14²

➢ 144 + c² = 196

➢ c² = 196 - 144

➢ c² = 52

➢ c = √52

➢ c = 7.21

Area = 1/2 × a × c

➢ 1/2 × 12 × 7.21

➢ 6 × 7.21

➢ 43.26 cm²

➢ 43.3 cm² [ round off to 1 decimal place ]

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