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vova2212 [387]
3 years ago
7

What is the reason for each step in the solution of the equation?

Mathematics
1 answer:
Luda [366]3 years ago
7 0
Isolate the variable by dividing each side by factors that don't contain the variable.
X=2
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A juice manufacturing company designed a carton as shown below. What is the name of the three-dimensional
kodGreya [7K]

Answer: rectangular prism and a pyramid I think

Step-by-step explanation:

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How should I explain how I know that 984/616 = 123/77 ?
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True they are equal

Step-by-step explanation:

123/77=

123×8/77×8

=984/616

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Convert 3.4 radians into degrees
Dafna11 [192]

Answer:

194.806

Step-by-step explanation:

To convert radians to degrees, the key is knowing that 180 degrees is equal to pi radians. Then multiply the measurement in radians by 180 divided by pi. For example, pi over 3 radians would be equal to 60 degrees.

to convert radians to degrees you first need to know that 180 degrees is equal to pi radians. then multiply the measurement in radians by 180 divided by pi. for example, pi over 3 radians would be equal to 60 degrees.

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3 years ago
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Determine whether the given system has a unique solution, no solution, or infinitely many solutions.
victus00 [196]

Answer:

The system has no solution.

Step-by-step explanation:

To find the solution to this system of linear equations

\left\begin{array}{ccccc}-3x_1&+x_2&-2x_3&=&8&\\x_1&+5x_2&-x_3&=&4&\\-x_1&+11x_2&-4x_3&=&1&\end{array}\right

First, state the problem in matrix form, this means, extracting only the numbers, and putting them in a box.

\left[ \begin{array}{ccc|c} -3 & 1 & -2 & 8 \\\\ 1 & 5 & -3 & 4 \\\\ -1 & 11 & -4 & 1 \end{array} \right]

This is called an augmented matrix. The word “augmented” refers to the vertical line, which we draw to remind ourselves where the equals sign belong

Next, transform the augmented matrix to the reduced row echelon form with the help of Row Operations.

Row Operation 1: multiply the 1st row by -1/3

\left[ \begin{array}{ccc|c} 1 & - \frac{1}{3} & \frac{2}{3} & - \frac{8}{3} \\\\ 1 & 5 & -1 & 4 \\\\ -1 & 11 & -4 & 1 \end{array} \right]

Row Operation 2: add -1 times the 1st row to the 2nd row

\left[ \begin{array}{ccc|c} 1 & - \frac{1}{3} & \frac{2}{3} & - \frac{8}{3} \\\\ 0 & \frac{16}{3} & - \frac{5}{3} & \frac{20}{3} \\\\ -1 & 11 & -4 & 1 \end{array} \right]

Row Operation 3: add 1 times the 1st row to the 3rd row

\left[ \begin{array}{ccc|c} 1 & - \frac{1}{3} & \frac{2}{3} & - \frac{8}{3} \\\\ 0 & \frac{16}{3} & - \frac{5}{3} & \frac{20}{3} \\\\ 0 & \frac{32}{3} & - \frac{10}{3} & - \frac{5}{3} \end{array} \right]

Row Operation 4: multiply the 2nd row by 3/16

\left[ \begin{array}{ccc|c} 1 & - \frac{1}{3} & \frac{2}{3} & - \frac{8}{3} \\\\ 0 & 1 & - \frac{5}{16} & \frac{5}{4} \\\\ 0 & 0 & 0 & -15 \end{array} \right]

Row Operation 5: add -32/3 times the 2nd row to the 3rd row

\left[ \begin{array}{ccc|c} 1 &- \frac{1}{3}  & \frac{2}{3} & - \frac{8}{3} \\\\ 0 & 1 & - \frac{5}{16} & \frac{5}{4} \\\\ 0 & 0 & 0 & -15 \end{array} \right]

Row Operation 6: multiply the 3rd row by -1/15

\left[ \begin{array}{ccc|c} 1 &- \frac{1}{3}  & \frac{2}{3} & - \frac{8}{3} \\\\ 0 & 1 & - \frac{5}{16} & \frac{5}{4} \\\\ 0 & 0 & 0 & 1 \end{array} \right]

Row Operation 7: add -5/4 times the 3rd row to the 2nd row

\left[ \begin{array}{ccc|c} 1 &- \frac{1}{3}  & \frac{2}{3} & - \frac{8}{3} \\\\ 0 & 1 & - \frac{5}{16} & 0 \\\\ 0 & 0 & 0 & 1 \end{array} \right]

Row Operation 8: add 8/3 times the 3rd row to the 1st row

\left[ \begin{array}{ccc|c} 1 &- \frac{1}{3}  & \frac{2}{3} & 0 \\\\ 0 & 1 & - \frac{5}{16} & 0 \\\\ 0 & 0 & 0 & 1 \end{array} \right]

Row Operation 9: add 1/3 times the 2nd row to the 1st row

\left[ \begin{array}{cccc} 1 & 0 & \frac{9}{16} & 0 \\\\ 0 & 1 & - \frac{5}{16} & 0 \\\\ 0 & 0 & 0 & 1 \end{array} \right]

The reduced row echelon form of the augmented matrix is

\left[ \begin{array}{cccc} 1 & 0 & \frac{9}{16} & 0 \\\\ 0 & 1 & - \frac{5}{16} & 0 \\\\ 0 & 0 & 0 & 1 \end{array} \right]

which corresponds to the system

\left\begin{array}{ccccc}x_1&&+\frac{9}{16} x_3&=&0&\\&1x_2&-\frac{5}{16}x_3&=&0&\\&&0&=&1&\end{array}\right

Equation 3 cannot be solved, therefore, the system has no solution.

7 0
4 years ago
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