Answer:
H=9;8)
B=(5;4) (ball)
R=(7;0) (hit point)
B'=symetric of B axis perpendicular of x in R
B'=(7+(7-5);4)=(9;4)
Equation BR: y-4=(0-4)/(7-5)(x-5)==>y=-2x+14
Equation RB': y-4=(4-0)/(9-7)(x-9)==>y=2x-14
Is H a point of RB'? y=2x-14 : 8=? 2*9-14==>8=?4 No!
you will not make your putt
Step-by-step explanation:
Answer:
sinФ = 8/17
cosФ = 15/17
tan Ф = 8/15
csc Ф = 17/8
sec Ф = 17/15
cot Ф = 15/8
Step-by-step explanation:
Let us revise the trigonometry functions
- Sin(x) = opposite/hypotenuse
- Cos(x) = adjacent/hypoteouse
- Tan(x) = opposite/adjacent
- Csc(x) = hypotenuse/opposit
- Sec(x) = hypotenues/adjacent
- Cot(x) = adjacent/opposite
In the given figure
The opposite side to angle Ф = 8
The adjacent side to angle Ф = 15
Find the hypotenuse using Pythagoras' theorem




Let us use the rules above to find the trigonometry functions
sinФ = 8/17
cosФ = 15/17
tan Ф = 8/15
csc Ф = 17/8
sec Ф = 17/15
cot Ф = 15/8
Answer: 1700.00
Step-by-step explanation: Maybe, maybe not.
Answer:
the answer is 1
Step-by-step explanation:
Answer:
55
Step-by-step explanation:
33/60 = 0.55 * 100 = 55
Check:
55*0.6 = 33
Hope that helps!