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3 years ago

What is an equation of the line that is perpendicular to y=-3/4x+6 and passes through the point (3,9)

Mathematics

1 answer:

goldenfox [79]3 years ago

5 0

Answer:

$y=\frac{4}{3}x+5$

Step-by-step explanation:

The line y= -3/4+6 in the comments has slope -3/4. A perpendicular line will have the negative reciprocal of -3/4. It's 4/3.

To write the equation, substitute 4/3 and the point (3,9) into

$y-y_1 = m(x-x_1)$

$y-9=\frac{4}{3}(x-3)\\\\y-9=\frac{4}{3}x -\frac{4*3}{3}\\\\y-9=\frac{4}{3}x-4\\\\y=\frac{4}{3}x+5$

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Given:
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