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3 years ago

What is an equation of the line that is perpendicular to y=-3/4x+6 and passes through the point (3,9)

Mathematics

1 answer:

goldenfox [79]3 years ago

5 0

Answer:

$y=\frac{4}{3}x+5$

Step-by-step explanation:

The line y= -3/4+6 in the comments has slope -3/4. A perpendicular line will have the negative reciprocal of -3/4. It's 4/3.

To write the equation, substitute 4/3 and the point (3,9) into

$y-y_1 = m(x-x_1)$

$y-9=\frac{4}{3}(x-3)\\\\y-9=\frac{4}{3}x -\frac{4*3}{3}\\\\y-9=\frac{4}{3}x-4\\\\y=\frac{4}{3}x+5$

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Consider F and C below. F(x, y, z) = y2 sin(z) i + 2xy sin(z) j + xy2 cos(z) k C: r(t) = t2 i + sin(t) j + t k, 0 ≤ t ≤ π (a) Fi

Liono4ka [1.6K]

Answer:

a) $f (x,y,z)= xy^2\sin(z)$

b) $\int_C F \cdot dr =0$

Step-by-step explanation:

Recall that given a function f(x,y,z) then $\nabla f = (\frac{\partial f}{\partial x},\frac{\partial f}{\partial y},\frac{\partial f}{\partial z})$ . To find f, we will assume it exists and then we will find its form by integration.

First assume that F = $\nabla f$ . This implies that

$\frac{\partial f}{\partial x} = y^2\sin(z)$ if we integrate with respect to x we get that

$f(x,y,z) = xy^2\sin(z) + g(y,z)$ for some function g(y,z). If we take the derivative of this equation with respect to y, we get

$\frac{\partial f}{\partial y} = 2xy\sin(z) + \frac{\partial g}{\partial y}$

This must be equal to the second component of F. Then

$2xy\sin(z) + \frac{\partial g}{\partial y}=2xy\sin(z)$

This implies that $\frac{\partial g}{\partial y}=0$ , which means that g depends on z only. So $f(x,y,z) = xy^2\sin(z) + g(z)$

Taking the derivative with respect to z and making it equal to the third component of F, we get

$xy^2\cos(z)+\frac{dg}{dz} = xy^2\cos(z)$

which implies that $\frac{dg}{dz}=0$ which means that g(z) = K, where K is a constant. So

$f (x,y,z)= xy^2\sin(z)$

b) To evaluate $\int_C F \cdot dr$ we can evaluate it by using f. We can calculate the value of f at the initial and final point of C and the subtract them as follows.

$\int_C F \cdot dr = f(r(\pi))-f(r(0))$

Recall that $r(\pi) = (\pi^2, 0, \pi)$ so $f(r(\pi)) = \pi^2\cdot 0 \cdot \sin(\pi) = 0$

Also $r(0) = (0, 0, 0)$ so $f(r(0)) = 0^2\cdot 0 \cdot \sin(0) = 0$

So $\int_C F \cdot dr =0$

5 0

3 years ago

Last year, Jason's average in math was a 72. This year, his average is a 90. What is the percent increase in Jason's grade?

slamgirl [31]

Answer:

20% increase

Step-by-step explanation:

All you have to do is divide 72 by 90n and it will give you .8, move the decimal two places to the right to give you 80 and subtract 80 from 100 to get 20

7 0

2 years ago

Find the percent of change. Where necessary, round to the nearest percent. Describe the percent of change as a percent of increa

deff fn [24]

70.17543859649122 percent change , rounded would be 70%, it is a 70% increase, as it goes to 57,000 to 97,000

6 0

3 years ago

Help me please, not very good at math. Thank u:)

ozzi

Answer:

76cm^2

Step-by-step explanation: