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eduard
2 years ago
6

Mr. Smith's class has 28 students. They all put in an equal amount of money to get Mr. Smith an end of year gift. If they collec

ted $168 altogether, how much money did each student give. For each question, define a variable (Let statement), write and solve an equation
Mathematics
1 answer:
ivann1987 [24]2 years ago
3 0

Answer:

Step-by-step explanation:

28 students all give $128

so,

\sqrt[28]{128}= v  v=6

Each student gave 6 dollars. This is true due to the fact that

\sqrt[28]{128}=6

28X6=128

You might be interested in
Johnson’s Hardware randomly selects 125 of its customers and questions them to determine their overall customer satisfaction rat
Sphinxa [80]

Answer:

a. 92%

b. 4425

Step-by-step explanation:

So there are 5000 customers in total, and 100 were completely satisfied, and 15 were satisfied and 10 weren't satisfied a bit. so 100+15 is 115 so 115 people in total were satisfied out of 125 because there were 125, and 115+10 is 125 anyways. So 115/125 is .92, and you can convert that into a percentage, 92% of the 250 customers were satisfied so then 250*5 is 5000, so then just multiply 115 by 5 as well. You get 575. So 575 were satisfied out of the 5000 customers and 5000-575 are the people not satisfied, so 4425.

probably wrong because it doesnt sound right but just try it

4 0
2 years ago
2x^2+3x-2, a=0 How do I find the derivative?
Ghella [55]

You can use the definition:

\displaystyle f'(x) = \lim_{h\to0}\frac{f(x+h)-f(x)}h

Then if

f(x) = 2x^2+3x-2

we have

f(x+h) = 2(x+h)^2+3(x+h) - 2 = 2x^2 + 4xh+2h^2+3x+3h-2

Then the derivative is

\displaystyle f'(x) = \lim_{h\to0}\frac{(2x^2+4xh+2h^2+3x+3h-2)-(2x^2+3x-2)}h \\\\ f'(x) = \lim_{h\to0}\frac{4xh+2h^2+3h}h \\\\ f'(x) = \lim_{h\to0}(4x+2h+3) = \boxed{4x+3}

I'm guessing the second part of the question asks you to find the tangent line to <em>f(x)</em> at the point <em>a</em> = 0. The slope of the tangent line to this point is

f'(0) = 4(0) + 3 = 3

and when <em>a</em> = 0, we have <em>f(a)</em> = <em>f</em> (0) = -2, so the graph of <em>f(x)</em> passes through the point (0, -2).

Use the point-slope formula to get the equation of the tangent line:

<em>y</em> - (-2) = 3 (<em>x</em> - 0)

<em>y</em> + 2 = 3<em>x</em>

<em>y</em> = 3<em>x</em> - 2

5 0
3 years ago
Can someone help with this please?
Tanzania [10]

Answer:

n=5 and it's output is -13

Step-by-step explanation:

By inspection, the inputs increase by +1 and the outputs decrease by 2

Thus ,n=4+1=5 and it's output is -11-2=-13

5 0
2 years ago
How do I solve? What do I do?
KonstantinChe [14]
I can’t really see the equation, what’s the equation? You can only see the bottom of it
7 0
2 years ago
Suppose that Theta is an angle in standard position whose terminal side intersects with the unit circle at (21/29,20/29). Fine t
kramer

Answer:

<u>The coordinates of the vertex is:</u>

  • x = 21/29, y = 20/29

Horizontal leg = x, vertical leg = 20/29, hypotenuse = 1 (radius of unit circle)

  • csc θ = hypotenuse / opposite = 1 / (20/29) = 29/20
  • cos θ = adjacent / hypotenuse = (21/29) / 1 = 21/29
  • cot θ = adjacent / opposite = (21/29) / (20/29) = 21/20
3 0
3 years ago
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