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KIM [24]
3 years ago
11

What is 4/5 of 500? Round it to the nearest hundredth

Mathematics
1 answer:
vaieri [72.5K]3 years ago
4 0
To be honest i have no idea what the answer is but do you know a sentence for the word scientific theory
You might be interested in
Answer the question :)
inn [45]

Answer:

A. -11

Step-by-step explanation:

In the function, replace x with -2

R(x) = x^2 - 3x - 1 ➡ R(-2) = (-2)^2 - 3 × 2 -1 = -11

5 0
3 years ago
On Monday 475 students went on a trip to the zoo. All 9 buses were filled and 7 students had to traveled in car . How many stude
KIM [24]

Answer:

52 students were in each bus

Step-by-step explanation:

475-7=468÷9=52 so 52

7 0
3 years ago
Write the equations of the following two sequences in "first term" form
mario62 [17]
A) Y = 100/10^x

B) Y = 0-50x
7 0
3 years ago
Read 2 more answers
What is the commom difference in the following arithmetic sequence??
aalyn [17]
Each increases by a certain amount called the common difference

4.4-2.8=1.6
6-4.4=1.6
7.7-6=1.7
hmm, some error
maybe you meant 7.6

common difference is 1.6

answer is C
5 0
3 years ago
Suppose 52% of the population has a college degree. If a random sample of size 563563 is selected, what is the probability that
amm1812

Answer:

The value is  P(| \^ p -  p| < 0.05 ) = 0.9822

Step-by-step explanation:

From the question we are told that

    The population proportion is  p =  0.52

     The sample size is  n  =  563      

Generally the population mean of the sampling distribution is mathematically  represented as

           \mu_{x} =  p =  0.52

Generally the standard deviation of the sampling distribution is mathematically  evaluated as

       \sigma  =  \sqrt{\frac{ p(1- p)}{n} }

=>      \sigma  =  \sqrt{\frac{ 0.52 (1- 0.52 )}{563} }

=>      \sigma  =   0.02106

Generally the  probability that the proportion of persons with a college degree will differ from the population proportion by less than 5% is mathematically represented as

            P(| \^ p -  p| < 0.05 ) =  P( - (0.05 - 0.52 ) <  \^ p <  (0.05 + 0.52 ))

  Here  \^ p is the sample proportion  of persons with a college degree.

So

 P( - (0.05 - 0.52 ) <  \^ p <  (0.05 + 0.52 )) = P(\frac{[[0.05 -0.52]]- 0.52}{0.02106} < \frac{[\^p - p] - p}{\sigma }  < \frac{[[0.05 -0.52]] + 0.52}{0.02106} )

Here  

    \frac{[\^p - p] - p}{\sigma }  = Z (The\ standardized \  value \  of\  (\^ p - p))

=> P( - (0.05 - 0.52 ) <  \^ p <  (0.05 + 0.52 )) = P[\frac{-0.47 - 0.52}{0.02106 }  <  Z  < \frac{-0.47 + 0.52}{0.02106 }]

=> P( - (0.05 - 0.52 ) <  \^ p <  (0.05 + 0.52 )) = P[ -2.37 <  Z  < 2.37 ]

=>  P( - (0.05 - 0.52 ) <  \^ p <  (0.05 + 0.52 )) = P(Z <  2.37 ) - P(Z < -2.37 )

From the z-table  the probability of  (Z <  2.37 ) and  (Z < -2.37 ) is

  P(Z <  2.37 ) = 0.9911

and

  P(Z <  - 2.37 ) = 0.0089

So

=>P( - (0.05 - 0.52 ) <  \^ p <  (0.05 + 0.52 )) =0.9911-0.0089

=>P( - (0.05 - 0.52 ) <  \^ p <  (0.05 + 0.52 )) = 0.9822

=> P(| \^ p -  p| < 0.05 ) = 0.9822

3 0
3 years ago
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