The perimeter of the equilateral triangle will be 76.2 in
<u>Explanation:</u>
Altitude of an equilateral triangle, H = 22 in
Perimeter, p = ?
Let a be the side of the triangle
We know:

Perimeter = 3a
P = 3 X 25.4 in
P = 76.2 in
Answer: The missing statements are,
In first blank: ∠2≅∠1
In second blank: AC≅AC
In third blank: Reflexive
Step-by-step explanation:
Since, The hypotenuse angle theorem states that if the hypotenuse and an acute angle of one right triangle are congruent to the hypotenuse and an acute angle of another right triangle, then the two triangles are congruent to each other.
Here, given:
∠D and ∠B are right angles.
DC ║ AB
Prove: Δ ADC ≅ Δ CBA
Statement Reason
1.∠D and ∠B are right angles 1. Given
2. ∠2 ≅ ∠1 2. If lines are parallel then interior angles
are equal
3. AC≅AC 3. Reflexive
4.Δ ADC ≅ Δ CBA 4. Hypotenuse angle theorem
Answer:
Therefore the variance on the data set is 8.3
Step-by-step explanation:
In order to find the variance of the set of data we first need to calculate the mean of the set, which is given by:
mean = sum of each element / number of elements
mean = (5 + 8 + 2 + 9 + 4)/5 = 5.6
We can now find the variance by applying the following formula:

So applying the data from the problem we have:
s² = [(5 - 5.6)² + (8 - 5.6)² + (2 - 5.6)² + (9 - 5.6)² + (4 - 5.6)²]/(5 - 1)
s² = [(-0.6)² + (2.4)² + (-3.6)² + (3.4)² + (-1.6)²]/4
s² = [0.36 + 5.76 + 12.96 + 11.56 + 2.56]/4 = 8.3
Therefore the variance on the data set is 8.3
notice, this will just be a Permutation.

you can always check your calculator also for a [ ₙPᵣ ] button.