1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
likoan [24]
3 years ago
12

Jack wants to fill a rectangular box with sand. The length of the sand box is 3 feet, width is 6 inches, and height is 2.4 inche

s. Each bag of sand contains 0.15 cubic foot of sand. How many bags of sand will Jack need to fill the box completely?
Mathematics
1 answer:
inna [77]3 years ago
7 0

Answer:

Jack needs 2 bags of sand.

You might be interested in
Show each step along the Way<br><br>Ur mom
LekaFEV [45]
2x+6 = 20
take 6 from both sides
2x = 14
divide by 2 on both sides
x = 7
8 0
3 years ago
50 POINTS!!
Andre45 [30]

Answer:Triangle A: 38 degrees

Triangle B: Unknown (not enough information)

Triangle C: Unknown (not enough information)

Triangle D: 70 degrees

Triangle E: 40 degrees

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
A box of 42 chocolates contains milk and dark chocolates in the ratio of 3:4. How many chocolates of each type there are?
Elza [17]
<h2>Answer:The number of milk chocolates are 18 and the number of dark chocolates are 24.</h2>

Step-by-step explanation:

Let the number of milk chocolates be m.

Let the number of dark chocolates be d.

Given that the box contains the milk and dark chocolates in the ratio 3:4.

So,\frac{m}{d}=\frac{3}{4}               ...(i)

Given that the total number of chocolates are 42.

So,m+d=42.                                   ...(ii)

Using (i) and (ii),

m+\frac{4}{3}m=42

\frac{7}{3}m=42

m=18

d=\frac{4}{3}m=\frac{4}{3}\times 18=24

So,the number of milk chocolates are 18 and the number of dark chocolates are 24.

4 0
3 years ago
A simple random sample of size n=14 is obtained from a population with μ=64 and σ=19.
madam [21]

Answer:

a) A. The population must be normally distributed

b) P(X < 68.2) = 0.7967

c) P(X  ≥  65.6) = 0.3745

Step-by-step explanation:

a) The population is normally distributed having a mean (\mu_x) = 64  and a standard deviation (\sigma_x) = \frac{19}{\sqrt{14} }

b) P(X < 68.2)

First me need to calculate the z score (z). This is given by the equation:

z=\frac{x-\mu_x}{\sigma_x} but μ=64 and σ=19 and n=14,  \mu_x=\mu=64 and \sigma_x=\frac{ \sigma}{\sqrt{n} }=\frac{19}{\sqrt{14} }

Therefore: z=\frac{68.2-64}{\frac{19}{\sqrt{14} } }=0.83

From z table, P(X < 68.2) = P(z < 0.83) = 0.7967

P(X < 68.2) = 0.7967

c) P(X  ≥  65.6)

First me need to calculate the z score (z). This is given by the equation:

z=\frac{x-\mu_x}{\sigma_x}

Therefore: z=\frac{65.6-64}{\frac{19}{\sqrt{14} } }=0.32

From z table,  P(X  ≥  65.6) =  P(z  ≥  0.32) = 1 -  P(z  <  0.32) = 1 - 0.6255 = 0.3745

P(X  ≥  65.6) = 0.3745

P(X < 68.2) = 0.7967

5 0
3 years ago
What is 6 times (12-4) in words?
Alika [10]
Six times twelve minus 4 equals forty-eight
3 0
3 years ago
Read 2 more answers
Other questions:
  • PLEASE HELP ME WITH THIS PROBLEM I HAVE BEEN STUCK ON IT FOR A WHILE!!!
    15·1 answer
  • Dada a função f(x) = ax + b e sabendo-se que f(3) = 5 e f(-2) = -5 calcule f(½)
    10·1 answer
  • Help me pleaseeee :)
    7·1 answer
  • All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be
    5·1 answer
  • Solve: 4x - 3 = x + 9
    15·2 answers
  • When you measure a person's weight, you are measuring the
    8·1 answer
  • Jim had 3 cups. He filled each cup 2 and 1/2 full of water. How much water is there altogether
    6·1 answer
  • If (2,0) is a solution of the linear equation 2x+3y=k,then the value of k is​
    12·2 answers
  • 8. An $18,000 car depreciates at a rate of 16% per year. How old will the car be when it is worth $12,000?
    6·1 answer
  • 7.5% of the grade has green eyes if there are 120 students in the grade how many dont have green eyes​
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!