Answer:
21+/-sqrt(253)=x
So one value for x is 21+sqrt(253)
and another is 21-sqrt(253)
Problem:
Given (21,7) and (x,1), find all x such that the distance between these two points is 17.
Step-by-step explanation:
Change in x is x-21
Change in y is 7-1=6
distance^2=(change in x)^2+(change in y)^2
17^2=(x-21)^2+(6)^2
289=(x-21)^2+36
Subtract 36 on both sides:
289-36=(x-21)^2
253=(x-21)^2
Take square root of both sides:
+/-sqrt(253)=x-21
Add 21 on both sides:
21+/-sqrt(253)=x
It would be B because you would take amelias age and take two away since todd is five years younger to get the a-5.
hope this helps :)
<span>m∠DEF= 1/2(the measure of the arc DEF
</span><span>m∠DEF= 1/2(232)
=116</span>
Answer:
1,560
it could be letter B
Step-by-step explanation:
I'm not sure about it but yeahh hope that helps
Answer:
![\sqrt[5]{x - 9}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%20-%209%7D%20)
Step-by-step explanation:
y=x^5+9
To find inverse function make x the subject, first:
y=x^5+9
y - 9 = x^5
x = ![\sqrt[5]{y - 9}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7By%20-%209%7D%20)
![y^{-1} = \sqrt[5]{x - 9}](https://tex.z-dn.net/?f=y%5E%7B-1%7D%20%20%3D%20%5Csqrt%5B5%5D%7Bx%20-%209%7D%20)
so inverse function of y=x^5+9 is
