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Hatshy [7]
3 years ago
13

In a pair of complementary angles, the measurement of the larger angle is three times that of the smaller angle. Find the measur

ements of the two angles.
Mathematics
2 answers:
Setler [38]3 years ago
7 0
So the meaning of two angles being complimentary simply means that the two angles add up to 90 degrees. Lets call the two angles x and y where x is the smaller angle.
x + y = 90
We also know that y, being the larger angle is 3 times x.
y = 3*x
Given these two we can solve the problem with basic algebra!
x + y =90
x + (3*x) = 90
4*x = 90
x = 90/4
x = 22.5
y = 3 * x
y = 3*(22.5)
y = 67.5
IgorC [24]3 years ago
5 0

Answer:

Angle L*; 67.5 degrees

Angle S*; 22.5 degrees

Step-by-step explanation:

Angle L is 3 times bigger than Angle S.

With this information, we can make an equation.

L=3S

Complementary angles add up to 90 degrees.

90 = 3S + S

90 = 4S

22.5

Angle S equals 22.5.

Because Angle L is 3 times bigger than Angle S, we multiply 22.5 by 3.

This gives us 67.5.

Angle L is 67.5 degrees

Angle S is 22.5 degrees

Now, in order to check our work, we add the two angles together.

67.5 + 22.5 = 90

Because they add up to 90 degrees, the complementary angles work with each other meaning that we are correct

*Angle L is the larger angle

**Angle S is the smaller angle

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disa [49]

Answer:

1)x=6

Step-by-step explanation:

step 1: add 2x to both sides.

x−15+2x=−2x+3+2x

3x−15=3

step 2: add 15 to both sides.

3x−15+15=3+15

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step 3: divide both sides by 3.

3x/3=18/3

x=6

answer:

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good luck :)

hopefully, this helps

i don't really know what it is that you need but **please let me know if this was incorrcect**

have a nice day !!

6 0
3 years ago
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Oduvanchick [21]

Answer:

Step-by-step explanation:

Put the equation in the form ax+by+c=0:

y\sqrt{3} =8x+\sqrt{3} \\=>8x-\sqrt{3} y+\sqrt{3} =0

Check the solutions:

(0,-1):

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8\sqrt{3} -9\sqrt{3} +\sqrt{3} =0

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3 years ago
The function rule of a certain function is y = -3x + 1. If the input is 7, what is the output?
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Answer:

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Who bout to do all this
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