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Leviafan [203]
3 years ago
8

PLEASE HELPPP

Mathematics
1 answer:
iVinArrow [24]3 years ago
3 0

Answer:

The electricity is $500 and the rent is $650.

Step-by-step explanation: I think you just subtract 650 from 1150.

You might be interested in
when a number is added to 1/5 of itself, the result is 24. the equation that models this problem is n 1/5 n = 24. what is the va
GuDViN [60]

Let n be unknown number, then 1/5 of this number is 1/5n. When you add these two numbers, you get

n+\dfrac{1}{5} n.

You know that this sum is equal to 24, so

n+\dfrac{1}{5} n=24.

1. Multiply this equation by 5:

5n+n=120.

2. Solve it:

6n=120,\\n=120:6,\\n=20.

Answer: n=20, correct choice is B.

4 0
3 years ago
Read 2 more answers
Help Plss <br>How many solutions do y=5-2x and 4x+2y = 10 have?​
tia_tia [17]

y=2x+5

2(2x+5)+4x=10

4x+10+4x=10

8x=20

So there's one solution, x=2.5

5 0
3 years ago
luis has three more quarters than dimes in his pocket, for a total of $1.80. How many dimes (x) are in his pocket
Dmitry_Shevchenko [17]

Answer:

3

Step-by-step explanation:

In this case, Luis has 6 quarters, and 3 dimes. 6 - 3 = 3, and it works out to the following:

6 • 0.25 = 1.50

3 • 0.10 = 0.30

1.50 + 0.30 = 1.80

8 0
3 years ago
You intend to estimate a population proportion with a confidence interval. The data suggests that the normal distribution is a r
SIZIF [17.4K]

Answer:

The critical value that corresponds to a confidence level of 99% is, 2.58.

Step-by-step explanation:

Consider a random variable <em>X</em> that follows a Binomial distribution with parameters, sample size <em>n </em>and probability of success <em>p</em>.

It is provided that the distribution of proportion of random variable <em>X, </em>\hat p, can be approximated by the Normal distribution.

The mean of the distribution of proportion is, \mu_{\hat p}=\hat p

The standard deviation of the distribution of proportion is, \sigma_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}.

Then the confidence interval for the population proportion <em>p</em> is:

CI=\hat p\pm z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n} }

The confidence level is 99%.

The significance level is:

\alpha =1-\frac{Confidence\ level}{100}=1-\frac{99}{100}=1-0.99=0.01

Compute the critical value as follows:

z_{\alpha /2}=z_{0.01/2}=z_{0.005}

That is:

P(Z>z)=0.005\\P(Z

Use the <em>z</em>-table for the <em>z-</em>value.

For <em>z</em> = 2.58 the P (Z < z) = 0.995.

And for <em>z</em> = -2.58 the P (Z > z) = 0.005.

Thus, the critical value is, 2.58.

7 0
4 years ago
Solve the equation by finding the common multiple.
Monica [59]

Answer:

1. 17/24

2. 1 1/8

3. 1 1/6

4. 1 5/24

5. 1. 1/4

6 0
3 years ago
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