Please help solvety

Mathematics

1 answer:

kobusy [5.1K]3 years ago

4 0

The answers are blurry and hard to read. If you repost this question with a clearer picture, I would be happy to try and answer as best I can! :)

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Find the solution of 3 times the square root of the quantity of x plus 6 equals negative 12, and determine if it is an extraneou

Anna35 [415]

For this case we have the following equation:
$3 \sqrt{x+6}=-12$
Rewriting we have:
$\sqrt{x+6}= \frac{-12}{3}$
$\sqrt{x+6}=-4$
We raise both members of the equation to the square:
$(\sqrt{x+6})^2=(-4)^2$
Rewriting we have:
$x+6=16$
$x=16-6$
$x=10$
It's a extraneous solution because equality is not met by substituting x = 10 in the original equation:
$3 \sqrt{10+6}=-12$
$3 \sqrt{16}=-12$
$3(4)=-12$
$12=-12$
Answer:
The solution is:
$x=10$
It's a extraneous solution

6 0

3 years ago

PLEASE HELP! WILL MARK BRAINLIEST!

____ [38]

Answer:

b. 75

Step-by-step explanation:

a(n) = a1 + d(n-1)

a(n) = 8.5 + 3.5(n - 1)

a(20) = 8.5 + 3.5(20 - 1)

a(20) = 8.5 + 3.5(19)

a(20) = 8.5 + 66.5