. There are 18 students in the Math Club. Of the 18 students 1/6 have red hair, 4/6 have brown hair and the rest have blonde hai
1 answer:
You might be interested in
Answer:
The maximum safe rescue height is 104.6 feet above the height of the ground.
Step-by-step explanation:
Consider a triangle ABC where C is the point where the rescue ladder is standing and AB be the building and Ladder making an angle of 72° as shown.
We have to find the height of the building.
Let x be the height of building
Using Trigonometric ratio,
So, the maximum safe rescue height is 104.6 feet above the height of
the ground.
Answer:
UV=29
Step-by-step explanation:
In right triangles AQB and AVB,
∠AQB = ∠AVB ...(i) {Right angles}
∠QBA = ∠VBA ...(ii) {Given that they are equal}
We know that sum of all three angles in a triangle is equal to 180 degree. So wee can write sum equation for each triangle
∠AQB+∠QBA+∠BAQ=180 ...(iii)
∠AVB+∠VBA+∠BAV=180 ...(iv)
using (iii) and (iv)
∠AQB+∠QBA+∠BAQ=∠AVB+∠VBA+∠BAV
∠AVB+∠VBA+∠BAQ=∠AVB+∠VBA+∠BAV (using (i) and (ii))
∠BAQ=∠BAV...(v)
Now consider triangles AQB and AVB;
∠BAQ=∠BAV {from (v)}
∠QBA = ∠VBA {from (ii)}
AB=AB {common side}
So using ASA, triangles AQB and AVB are congruent.
We know that corresponding sides of congruent triangles are equal.
Hence
AQ=AV
5x+9=7x+1
9-1=7x-5x
8=2x
divide both sides by 2
4=x
Now plug value of x=4 into UV=7x+1
UV=7*4+1=28+1=29
<u>Hence UV=29 is final answer.</u>
