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shusha [124]
4 years ago
14

What is the sign of a.

Mathematics
1 answer:
posledela4 years ago
6 0

As a = 0 , there is no sign . Its only 0. Thus the answer is (c)

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What is the approximate volume of the cone? Use 3.14 for it.help please
Vesna [10]

Answer:

157.08, so it is the first opition

Step-by-step explanation

Volume of a cone is pie x the radius squared by 2 x the hieght divided by 3

pie x 5^2 x 6/3

pie x 25 x 2

157.08

3 0
3 years ago
5 chocolates cost $15 what will 15 chocolates cost
zaharov [31]
Im pretty sure the answer is $45.
4 0
3 years ago
Read 2 more answers
A rectangle is 6 feet long and 4 feet wide. If each dimension is increased by the same number of feet, a new rectangle is formed
Fofino [41]

Answer:

Each dimension increased by 3 ft.

Step-by-step explanation:

Area of the original rectangle = 4 * 6 = 24 square feet

Increased dimension = x ft

New length = 6 + x

New width = 4 +x

New area = (6 + x)(4 +x)    {Use FOIL method}

                = 6*4 + 6*x + x*4 + x*x

                = 24 + 6x + 4x + x²

                = x² + 10x + 24

New area = 24 + 39

x² + 10x + 24 = 63

x² +10x + 24 - 63 = 0

x² + 10x  - 39 = 0

x² + 13x - 3x  - 3*13 = 0

x (x + 13) - 3(x + 13) = 0

(x + 13)(x -3) = 0   {Ignore x + 13, as it gives negative value}

x - 3 = 0

x = 3

5 0
3 years ago
3 units to the left of 0
Ket [755]
-3...idk what your asking...but on a number line, 3 places to the left of zero is negative three
4 0
3 years ago
Write the left side of each equation as a product of linear factors, and state the solutions.
Amiraneli [1.4K]

Answer:

a). x_{1}=1, x_{2}=1,x_{3}=1

b). x_{1}=2, x_{2}=2, x_{3}=2

c). x_{1} = \sqrt{-5}, x_{2} = \sqrt{-5}, x_{2} = \sqrt{-2},x_{4} = \sqrt{-2}

Step-by-step explanation:

a.

x^{3}-1=0\\x^{3}=1\\ x=(1 )^{\frac{1}{3} }

x=1

b.

x^{3}+8=0\\x^{3}=-8\\ x=(-8 )^{\frac{1}{3} }

x= 2i

c.

x^{4} +7x^{2} +10=0\\x^{4}=u^{2} \\x^{2}=u\\ u^{2}+7u+10=0\\

Using

\frac{-b+/-\sqrt{7^{2}-4*a*c } }{2*a}

u=\frac{-7+/-\sqrt{7^{2}-4*10}}{2}=-\frac{7}{2} +/- \frac{\sqrt{49-40} }{2} \\ u=-\frac{7}{2} +/- \frac{3}{2} \\u_{1}= -5\\u_{2}= -2

But u is no the factor is x so:

x=\sqrt{u}\\ x_{1} =\sqrt{-5} =5i\\ x_{2} =\sqrt{-2} =2i

Check:

(\sqrt{5i})^{4} +7*(\sqrt{5i})^{2}  +10=0\\25*i^{4} +7*5*i^{2}+10=0\\ 25*1+7*5*-1+10\\25-35+10=0\\0=0

4 0
4 years ago
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