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shusha [124]
3 years ago
14

What is the sign of a.

Mathematics
1 answer:
posledela3 years ago
6 0

As a = 0 , there is no sign . Its only 0. Thus the answer is (c)

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Bev earns $2 a week for taking out her neighbor’s trash cans. Complete the table of values. Then state the domain and range.
Eduardwww [97]

Domain : \{1,2,3,4\}

Range: \{2,4,6,8\}

Explanation:

It is given that Bev earns $2 a week.

Thus, for n number of weeks, we shall multiply $2 with n.

Where n=1,2,3,4 is the number of weeks.

For 1 week, Bev earns 2n=2(1)=2 ⇒ $2

For 2 weeks, Bev earns 2n=2(2)=4 ⇒ $4

For 3 weeks, Bev earns 2n=2(3)=6 ⇒ $6

For 4 weeks, Bev earns 2n=2(4)=8 ⇒ $8

Thus, we can see that the domain is the number of weeks.

Hence, Domain : \{1,2,3,4\}

Also, the money earned is the range.

Hence, Range: \{2,4,6,8\}

6 0
3 years ago
What is the solution to -3/7m&lt;21?<br><br> m &lt; 49<br> m &gt; 49<br> m &gt; -49<br> m &lt; -49
DENIUS [597]

Answer:

Step-by-step explanation:

hello :

-3/7m<21  

multiply by (-1) : 3/7m > 21

now dividid by 3/7 : m > 21×7/3

m > 49

4 0
3 years ago
What is 60 divided by 1/5?
larisa [96]
60 divided by 1/5 (.2) is 300
6 0
3 years ago
QUICKK ANSWERR (will mark brainlist)
atroni [7]

Answer:

Jessie sold x DVDs for $<u>3</u> each and then sold a board game for $<u>12</u>. Jessie made (select) $27 in her sales. How many DVDs did she sell?

She sold 5 DVDs

Step-by-step explanation:

3x+12=27

3x=15

x=5

5 DVDS

4 0
3 years ago
A track-and-field athlete releases a javelin. The height of the javelin as a function of time is shown on the graph below. Use t
Georgia [21]
Part 1:
 
 For this case we must see in the graph the axis of symmetry of the given parabola.
 We have then that the axis of symmetry is the vertical line t = 2.
 Answer:
 
The height of the javelin above the ground is symmetric about the line t = 2 seconds:

 
Part 2:

 
For this case, we must see the time t for which the javelin reaches a height of 20 feet for the first time.
 We then have that when evaluating t = 1, the function is h (1) = 20. To do this, just look at the graph.
 Then, we must observe the moment when it returns to be 20 feet above the ground.
 For this, observing the graph we see that:
 h (3) = 20 feet
 Therefore, a height of 20 feet is again reached in 3 seconds.
 Answer:
 
The javelin is 20 feet above the ground for the first time at t = 1 second and again at t = 3 seconds
5 0
3 years ago
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