-19m-19 = 4m-4m+19
-19m-19 = 0+19
-19m = 19+19
-19m = 38
m = 38÷(-19)
m = -2
Answer:
195
Step-by-step explanation:
87+38+40=165
360-165=195
Hope this helps!
If not, I am sorry.
A pyramid is regular if its base is a regular polygon, that is a polygon with equal sides and angle measures.
(and the lateral edges of the pyramid are also equal to each other)
Thus a regular rectangular pyramid is a regular pyramid with a square base, of side length say
x.
The lateral faces are equilateral triangles of side length
x.
The lateral surface area is 72 cm^2, thus the area of one face is 72/4=36/2=18 cm^2.
now we need to find
x. Consider the picture attached, showing one lateral face of the pyramid.
by the Pythagorean theorem:

thus,

thus:

(cm^2)
but

is exactly the base area, since the base is a square of sidelength =
x cm.
So, the total surface area = base area + lateral area =

cm^2
Answer:

cm^2
Answer:
<em>x = 1</em>
<em>y = 1</em>
Step-by-step explanation:
<u>System of Equations</u>
We are given the system of equations:
2x + y = 3
x = 2y - 1
Substituting x in the first equation:
2(2y - 1) + y = 3
Operating:
4y - 2 + y = 3
5y = 3 + 2
y = 5/5 = 1
y = 1
Since:
x = 2y - 1
Then:
x = 2(1) - 1
x = 1
Solution:
x = 1
y = 1
<u>Given</u>:
If you are dealt 4 cards from a shuffled deck of 52 cards.
We need to determine the probability of getting two queens and two kings.
<u>Probability of getting two queens and two kings:</u>
The number of ways of getting two queens is 
The number of ways of getting two kings is 
Total number of cases is 
The probability of getting two queens and two kings is given by

Substituting the values, we get;

Simplifying, we get;



Thus, the probability of getting two queens and two kings is 0.000133