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2 years ago

SOMEONE PLEASE HELP ASAP!!!!!

Mathematics

1 answer:

Margaret [11]2 years ago

7 0

Answer:

x = 1

y = 1

Step-by-step explanation:

System of Equations

We are given the system of equations:

2x + y = 3

x = 2y - 1

Substituting x in the first equation:

2(2y - 1) + y = 3

Operating:

4y - 2 + y = 3

5y = 3 + 2

y = 5/5 = 1

y = 1

Since:

x = 2y - 1

Then:

x = 2(1) - 1

x = 1

Solution:

x = 1

y = 1

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HELP PLEASE

Georgia [21]

Answer:

$\huge\boxed{\sf No}$

Step-by-step explanation:

Evan spent 20 hours doing homework last week

25 hours were spent this week.

Let's see what 125% of 20 equals:

= (125 / 100) * 20

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= 25 hours

But,

It is written that Evan thought he spent 125 % more than the last week which means:

= (125% of 20) + 20

= 25 + 20

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He should've said that he has given 25% more time than the last week.

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$\rule[225]{225}{2}$

Hope this helped!

7 0

2 years ago

Find the solution of the given initial value problem. ty' + 2y = sin t, y π 2 = 9, t > 0 y(t) =

Helen [10]

For the ODE

$ty'+2y=\sin t$

multiply both sides by t so that the left side can be condensed into the derivative of a product:

$t^2y'+2ty=t\sin t$

$\implies(t^2y)'=t\sin t$

Integrate both sides with respect to t :

$t^2y=\displaystyle\int t\sin t\,\mathrm dt=\sin t-t\cos t+C$

Divide both sides by $t^2$ to solve for y :

$y(t)=\dfrac{\sin t}{t^2}-\dfrac{\cos t}t+\dfrac C{t^2}$

Now use the initial condition to solve for C :

$y\left(\dfrac\pi2\right)=9\implies9=\dfrac{\sin\frac\pi2}{\frac{\pi^2}4}-\dfrac{\cos\frac\pi2}{\frac\pi2}+\dfrac C{\frac{\pi^2}4}$

$\implies9=\dfrac4{\pi^2}(1+C)$

$\implies C=\dfrac{9\pi^2}4-1$

So the particular solution to the IVP is

$y(t)=\dfrac{\sin t}{t^2}-\dfrac{\cos t}t+\dfrac{\frac{9\pi^2}4-1}{t^2}$

$y(t)=\dfrac{4\sin t-4t\cos t+9\pi^2-4}{4t^2}$

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2 years ago