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Anika [276]
3 years ago
7

Find the solution set x^2 - 5x =0 separated the two values with commas

Mathematics
1 answer:
Sonja [21]3 years ago
4 0

Answer:

<h3>x(x-5)=0</h3><h3>(x+1)(x-5)=0</h3><h3>x+1=0 or x-5=0</h3><h3>x=-1 or+5</h3><h3>x={-1,+5}</h3>
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Joanna is selling tickets for the school play $he ha$ already $old $35
Nonamiya [84]

Answer:

okay, so given we have that she has already sold $35 worth of tickets. We know that she has seven tickets left to sell, and each is worth $5. So, we would do 7×$5=$35

Next, we would add $35(from the previous money she has made) and $35 (the money she just made from the 7 tickets) and that would equal $70

equation: y=35+7(5)

Step-by-step explanation:

I hope this helps! ^^

☁️☁️☁️☁️☁️☁️☁️☁️☁️

4 0
3 years ago
To create the flower gardens, Wendell bought six pieces of wood. Pieces A and B are 6 feet long, pieces C and D are 8 feet long,
Korolek [52]

Answer:

Step-by-step explanation:

5 0
3 years ago
The person who answers has an explanation that doesn't have a link, and isn't incorrect gets brainiest. Ok here is the question
Shtirlitz [24]

Answer:

3.1415926535897932384626433832795028841971693993751058209749445923078164062862089986280348253421170679

5 0
2 years ago
Read 2 more answers
Which equation represents the line shown in the graph?
Verizon [17]
Answer: C

The slope is y = -1/2x
4 0
3 years ago
PLEASE help with these questions??<br> there are 7 of them!<br> Thank you!!
svetlana [45]
We know in these kind of triangles that have a 90 degrees angle, we can do:

{a}^{2} + {b}^{2} = {c}^{2}

so the first question:

\sqrt{ {99}^{2} + {20}^{2} } = 101

and then:

b = \sqrt{ {17}^{2} - {15}^{2} } = 8

so , when you want to rationalize , usually you must multiply the irrational factor as 1:

\frac{ \sqrt{15} }{ \sqrt{15} } = 1

so , now multiply:

\frac{3}{ \sqrt{15} } \times \frac{ \sqrt{15} }{ \sqrt{15} } = \frac{3 \sqrt{15} }{15} = \frac{ \sqrt{15} }{5}

in the next question,we know negative numbers in radical don't have any solution so 2 is correct,

4 0
2 years ago
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