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Alexandra [31]
3 years ago
12

What is a correct congruence statement for the triangles shown?

Mathematics
1 answer:
lina2011 [118]3 years ago
4 0
The correct congruence statement for the triangles shown is∆ BLG~=∆PFX.
You might be interested in
- Andy wants to rent a one-bedroom apartment in Green Acres. The apartment has a monthly rent of
rjkz [21]

Answer:

$161.88

Step-by-step explanation:

1, 425 * 0.05 = 71.25 = yearly

71.25 / 12 = 5.94 = monthly

5.94 * 2 = 11.88 = for two months

11.88 + 150 = 161.88 = the amount he is expected to pay

Tell me if I'm wrong :)

8 0
2 years ago
In a particular faculty 60% of students are men and 40% are women. In a random sample of 50 students what is the probability tha
zimovet [89]

Answer:

a) The expected value is given by:

E(X) = np = 50*0.4 = 20

and the variance is given by:

Var(X) =np(1-p) = 50*0.4*(1-0.4) = 12

b) P(X>25)= 1-P(X\leq 25)

And we can find this probability with the following Excel code:

=1-BINOM.DIST(25,50,0.4,TRUE)

And we got:

P(X>25)= 1-P(X\leq 25)=0.0573

c) 1) Random sample (assumed)

2) np= 50*0.4= 20 >10

n(1-p) =50*0.6= 30>10

3) Independence (assumed)

Since the 3 conditions are satisfied we can use the normal approximation:

X \sim N(\mu = 20 , \sigma= 3.464)

d) P(X>25) = 1-P(Z< \frac{25-20}{3.464}) = 1-P(z

e) P(X>25)= P(X>25.5) = 1-P(X \leq 25.5)

P(X>25)= P(X>25.5) = 1-P(X \leq 25.5)= 1-P(Z

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=50, p=0.4)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

Part a

The expected value is given by:

E(X) = np = 50*0.4 = 20

and the variance is given by:

Var(X) =np(1-p) = 50*0.4*(1-0.4) = 12

Part b

For this case we want to find this probability:

P(X>25)= 1-P(X\leq 25)

And we can find this probability with the following Excel code:

=1-BINOM.DIST(25,50,0.4,TRUE)

And we got:

P(X>25)= 1-P(X\leq 25)=0.0573

Part c

1) Random sample (assumed)

2) np= 50*0.4= 20 >10

n(1-p) =50*0.6= 30>10

3) Independence (assumed)

Since the 3 conditions are satisfied we can use the normal approximation:

X \sim N(\mu = 20 , \sigma= 3.464)

Part d

We want this probability:

P(X>25) = 1-P(Z< \frac{25-20}{3.464}) = 1-P(z

Part e

For this case we use the continuity correction and we have this:

P(X>25)= P(X>25.5) = 1-P(X \leq 25.5)

P(X>25)= P(X>25.5) = 1-P(X \leq 25.5)= 1-P(Z

4 0
3 years ago
Hey can you please help me posted picture of question
SpyIntel [72]
We are to find the Probability the someone buys a book that is paperback and fiction.

Let P(F) represents the event that the book is fiction and P(P) represents the event that the book is paperback. We are to find P(F∩P)

P(F∩P) = P(F) x P(P)

From the tree diagram we can see that:

P(F) = 0.45
P(P) = 0.65

Using the values, we get:

P(F∩P) = 0.45 x 0.65 = 0.2925

So, the Probability the someone buys a book that is paperback and fiction is 0.2925.

So, option B gives the correct answer
3 0
3 years ago
Emma received a $40 gift card that could be used to download television programs. After downloading 5 programs, she had $30 rema
aalyn [17]

Answer:

x= 1 program

x= $2

Step-by-step explanation:

40-30= 10 <- what she spent

10/5 = 2

5 = Amount of Programs

Each program is $2.

Your welcome :)

8 0
3 years ago
After how many audio books will both book clubs cost the same amount.​
bulgar [2K]

Answer:

2 books

Step-by-step explanation:

10 + 5x = 16 + 2x

    - 2x         - 2x

10 + 3x = 16

-10          -10

3x = 6

/3    /3

<u>x = 2</u>

4 0
2 years ago
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