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Tems11 [23]
2 years ago
5

What is the correct name

Chemistry
2 answers:
Inessa05 [86]2 years ago
5 0

Answer:

The Answer is 2-methylpentane

Or the third one down.

Explanation:

Yuri [45]2 years ago
3 0

BEST ANSWER IS

C

is 2-methylpentane

HOPE YOU PASSS

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Which of the following is true: A. Gamma rays are too dangerous to be used in a medicinal way. B. Gamma radiation is used common
ratelena [41]

Answer:

D

Explanation:

Gamma radiation penetrates the cell wall of prokaryotic organisms such as bacteria and can inhibit their metabolic functions as well as destroy their DNA.

Debunking the other answers:

A is incorrect as Gamma radiation is used in the treatment of cancer via radiotherapy.

B is incorrect as Gamma rays are too small and would just penetrate any smoke particles.

C is incorrect because Gamma rays are used to disinfect food products to prevent food borne illness. Irradiation is safe to use on food and does not make it radioactive.

Thus, D is correct.

6 0
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Calculate RMM given Aluminium sulphate given RAM: A1-27; S-32; 0-16
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2 years ago
Which of the following is an intensive property?
PilotLPTM [1.2K]
I believe the answer is A
6 0
3 years ago
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15.89 percent carbon, 21.18 percent oxygen, and 62.93 percent osmium. what is the empirical formula
otez555 [7]

Answer:

OsCO or COOs

Explanation:

Data given

Carbon = 15.89 %

Oxygen = 21.18 %

Osmium = 62.93%

Empirical formula = ?

Solution:

First find the masses of each component

Consider total compound is 100g

As we now

mass of element = % of component

So,

15.89 g of C     = 15.89 % Carbon

21.18 g of O      =   21.18 % Oxygen

62.93 g of Os  =   62.93% Osmium

Now convert the masses to moles

For Carbon

Molar mass of C = 12 g/mol

                  no. of mole = mass in g / molar mass

Put value in above formula

                  no. of mole =  15.89 g/ 12 g/mol

                  no. of mole =  1.3242

mole of C = 1.3242

For Oxygen

Molar mass of O = 16 g/mol

                  no. of mole = mass in g / molar mass

Put value in above formula

                  no. of mole =  21.18 g/ 16 g/mol

                  no. of mole =  

mole of O = 1.3238

For Os

Molar mass of Os = 190 g/mol

                  no. of mole = mass in g / molar mass

Put value in above formula

                  no. of mole =  62.93 g/ 190 g/mol

                  no. of mole =  

mole of Os = 1.3312

Now we have values in moles as below

C = 1.3242

O = 1.3238

Os = 1.3312

Divide the all values on the smalest values to get whole number ratio

C = 1.3242 /1.3238 = 1.0003

O = 1.3238 /1.3238 = 1

Os = 1.3312 /1.3238 = 1.0056

So all have round value 1 mole

C = 1

O = 1

Os = 1

So the empirical formula will be (OsCO) i.e. all 3 atoms in simplest small ratio

7 0
3 years ago
The _____ is the attraction of the electrons of one atom to the protons of the other atom, leading to a bond.
Pavel [41]

Answer:

i donr reagly knove

Explanation: yeah i dont know

3 0
2 years ago
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