35g Mg x 1mol / 24g = 840 mol
Answer:
12.5mm
Explanation:
1cm = 10mm
so you need to multiply the 1.25 by 10 to get it in mm.
Answer:
Concept: Chemical Analysis
- You need to start by graphing the data and then analyzing it.
- We can see that the horse has a distance in meters of 980 at the end of the 10 seconds hence it is the fastest.
- The horse line has a linearly representation, while the alternate line has parabolic tendencies towards the end. The steeper line indicates a faster change in time or velocity which results in a greater distance traveled indicating that the horse is faster.
- *I have confidence you can graph that*
A very hot but containable and easy or legal container so it doesn't explode , thermometer but advanced so it doesn't burn and gloves maybe oven mitts and if u were doing it at home other safety equipment
Answer:
Here's what I get
Step-by-step Explanation
(a) Effect of dilution
There will be no effect on the volume of NaOH needed.
The amount of HCl will be halved, so the amount of NaOH will be halved.
However, the concentration of NaOH is also halved, so you will need twice the volume.
You will be back to the same volume as before dilution.
(b) Net ionic equation
Molecular: HCl(aq)+NaOH(aq)→NaCl(aq)+H2O(l)
Ionic: H⁺(aq) + Cl⁻(aq) + Na⁺(aq) + OH⁻(aq) ⟶ Na⁺(aq) + Cl⁻(aq) + H₂O(l)
Net ionic: H⁺(aq) + OH⁻(aq) ⟶ H₂O(l)
(c) Proton acceptor
H⁺ is the proton. OH⁻ accepts the proton and forms water.
(d) Moles of HCl

(e) Equivalence point
The equivalence point is the point at which the titration curve intersects the pH 7 line.
(f) Schematic representation
Assume the box for 0.10 mol·L⁻¹ HCl contains four black dots (H⁺) and four open circles (Cl⁻).
The 0.20 mol·L⁻¹ solution is twice as concentrated.
It will contain eight black dots and eight open circles.