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skad [1K]
3 years ago
10

What are the chemical names for KF

Chemistry
1 answer:
den301095 [7]3 years ago
7 0
Um, I think it’s: k is potassium and F is fluorine so potassium Fluoride
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Hexanal would be soluble in water? True or false?
telo118 [61]

Answer:

False.

Explanation:

Hexanal is a non-polar compound while water is a polar solvent.

We have the role "Like dissolves like".

So, hexanal is insoluble in water.

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3 years ago
Part A<br> How does a bicycle make work easier?<br> VIDEO TELLS U NOTHING
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3 years ago
Enter the number of unique signals in the 1H NMR spectrum of ethanol. Assume that the hydroxy proton does NOT exchange with the
ss7ja [257]

Answer:

In the 1H NMR spectrum of ethanol three different signals are observed, this is due to the existence of 3 types of hydrogens with different chemical environment. Hydrogens A (3.57 ppm) are more screened than C (1.10 ppm) due to the presence of oxygen (electonegative atom that removes electron density). The chemical environment of hydrogen B (4.78 ppm), attached directly to oxygen, is also different by resonating at a frequency different from the previous ones.

C1HC_{3} -C2HA_{2} -OHB

The hydroxylic hydrogen produces a singlet, the pair of carbon hydrogens one give rise to a quadruplet and the three hydrogens of carbon two produce a triplet.

Explanation:

5 0
3 years ago
Rb2co3(aq)+fec2h302(aq)--&gt;
nata0808 [166]

Answer:

Rb2CO3(aq)+Fe(C2H3O2)2(aq)--> 2Rb(C2H3O2)(aq) + FeCO3(s)

Explanation:

The reaction shown in the answer is the reaction of rubidium carbonate and iron II acetate. Rubidium is far more reducing than Fe II hence it can displace Fe II from its salt as shown.

The reducing property of metals depends on the value of their individual electrode potential values. For rubidium, its standard reduction potential is -2.98 V while that of Fe II is -0.44V. Hence rubidium can displace Fe II from its salt as shown above.

4 0
3 years ago
The molar mass of H2O is 18.01 g/mol. The molar mass of O2 is 32.00 g/mol. What mass of H2O, ins grams, must react to produce 50
Ivan

Answer:

56.28 g

Explanation:

First change the grams of oxygen to moles.

(50.00 g)/(32.00 g/mol) = 1.5625 mol O₂

You have to use stoichiometry for the next part.  Looking at the equation, you can see that for every 2 moles of H₂O, 1 mole of O₂ is produced.  Convert from moles of O₂ to moles of H₂O using this relation.

(1.5625 mol O₂) × (2 mol H₂O/1 mol O₂) = 3.125 mol H₂O

Now convert moles of H₂O to grams.

(3.125 mol) × (18.01 g/mol) = 56.28125 g

Convert to significant figures.

56.28125 ≈ 56.28

5 0
3 years ago
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