Given:
A compound with:
Number of carbon atoms = 9
Number of double bonds = 1
A double bond between 5th and 6th carbon
A propyl group (CH2CH2CH3) branching off the 3rd carbon from the left
Try to illustrate the given and observe the formation of the atoms. Now, follow the correct IUPAC naming system. The name of the compound is
4-propyl-1-hexene
Count from the right to the left, the double bond is between the 1st and 2nd carbon, thus, 1-hexene. The propyl branches out the 4th carbon from the right, thus 4-propyl.
Answer: 2m/s^2
Explanation:
Velocity of skateboard = 20.0 m/s.
Time taken = Ten seconds (10 s)
Acceleration = ?
Recall that acceleration is the change in velocity of a body per unit time.
i.e Acceleration = (velocity / Time)
Acceleration = 20.0m/s ➗ 10 s
Acceleration = 2m/s^2
Thus, Jeffrey acceleration was 2m/s^2
