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miv72 [106K]
4 years ago
5

In two or more complete sentences explain how to balance the chemical equation and classify its reaction type.

Chemistry
1 answer:
sleet_krkn [62]4 years ago
8 0

<u>Answer:</u> The given chemical reaction is a single displacement reaction.

<u>Explanation:</u>

Single displacement reaction is defined as the reaction in which more reactive metal displaces the less reactive metal from its chemical reaction.

The reactivity of metal is determined by a series known as reactivity series. The metals lying above in the series are more reactive than the metals which lie below in the series.

A+BC\rightarrow AC+B

Metal A is more reactive than Metal B.

A balanced chemical equation is defined as the equation in which total number of individual atoms on the reactant side is equal to the total number of individual atoms on the product side. These equations follow law of conservation of mass.

For the given chemical reaction:

2Al(s)+3CuSO_4(aq.)\rightarrow Al_2(SO_4)_3(aq.)+3Cu(s)

By Stoichiometry of the reaction:

2 moles of aluminium metal reacts with aqueous solution of copper sulfate to produce 1 mole of aqueous solution of aluminium sulfate and 3 moles of copper metal.

Hence, the given chemical reaction is a single displacement reaction.

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Which statement best describes the collisions of gas particles according to the kinetic-molecular theory?
Andrew [12]

Answer:

b. As particles travel in straight lines, their paths sometimes meet, and then they bounce apart with no gain or loss of energy.

Explanation:

Kinetic - molecular theory -

According to this theory , gas is considered to be as a large number of very small particles , which moves randomly , and due to this randomness collisions occurs , as the particles collide with each other and the wall of the container .

During these collisions , there is no loss or gain of energy , there is only transfer of energy .

3 0
3 years ago
Read 2 more answers
A student pipets exactly 5.00ml of 3.47 x 10.2M FeCl3 solution into a Vol flask and adds enough water to it to make 250ml of sol
andrew-mc [135]

Answer:

The concentration would be 0.76 mol/L.

The most common way to solve this problem is to use the formula

c1V1=c2V2

In your problem,

c1 = 4.2 mol/L; V1 = 45.0 mL

c2 = ?; V2 = 250 mL

c2=c1×V1V2 = 4.2 mol/L × 45.0mL250mL = 0.76 mol/L

This makes sense. You are increasing the volume by a factor of about 6, so the concentration should be about ¹/₆ of the original (¹/₆ × 4.2 = 0.7).

Explanation:

if it is helpful...... plzz like and follow

5 0
3 years ago
BRAINLIESTTT ASAP!! PLEASE HELP ME :)
horsena [70]

Answer: Hard working,satisfied. (i think)

~Please mark as brainiest~

3 0
4 years ago
Read 2 more answers
9. What is the total number of grams of NaOH (formula mass = 40.) needed to make 1.0 liter of a 0.20 M solution?
xxTIMURxx [149]

Answer:

8 gram

Explanation:

in case of NaOH, normality=molarity

so normality=molarity×acidity or basicity(in case of NaOH it's 1)

then

weight of NaOH required = volume in ml × equivalent weight × normality / 1000

so

1000× 40× 0.2/1000

=8 gram

3 0
3 years ago
Plz help asap. answer needed!!!
cricket20 [7]

Answer:

11.43g of Aluminum Hydroxide

Explanation:

Since we know that the sulfuric acid is the limiting reactant in this chemical reaction, we know that we are going to be left with excess aluminum hydroxide. So to find the amount of leftover aluminum hydroxide we are going to need to convert the given amount of sulfuric acid to the amount of aluminum hydroxide needed to react with the sulfuric acid.

\frac{35g H_{2}SO_{4}}{1}*\frac{1 mole H_{2}SO_{4}}{98.079 g H_{2}SO_{4}} *\frac{2 moles Al(OH)_{3} }{3 moles H_{2}SO_{4}} * \frac{78.003 g Al(OH)_{3} }{1 mole Al(OH)_{3} } = 18.557 g Al(OH)_{3}

Once you do that, you need to subtract that number from the amount of aluminum hydroxide given to get the amount of left over aluminum hydroxide.

30 g Al(OH)_{3} - 18.557 g Al(OH)_{3} = 11.43 g Al(OH)_{3}

Hope this helps!

5 0
3 years ago
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