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3 years ago

13

What is the solution to StartFraction h over negative 24 EndFraction less-than-or-equal-to 18?

2 answers:

Lisa [10]3 years ago

5 0

The answer is D. h is greater-than-or-equal-to negative 432. I hope this helps.

Lyrx [107]3 years ago

5 0

Answer:

D

Step-by-step explanation:

took the test

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Lilli jogs 12 mile in 110 hour What is Lilli's rate in miles per hour?

Verizon [17]

The problem requires us to find the rate or speed of Lilli in miles per hour. Therefore, we just have to divide the given data.

12/110 = 0.10909.... Therefore, Lilli's speed or rate is 0.11 mi/hr.

5 0

4 years ago

Mai and Priya were on scooters. Mai traveled 15 meters in 6 seconds. Priya travels 22 meters in 10 seconds. Who was moving faste

Andrews [41]

Answer:

Mai was moving faster.

As, she covered a greater distance in the same amount of time.

Step-by-step explanation:

Given: Mai traveled 15 meters in 6 seconds and Priya travels 22 meters in 10 second.

Calculate the speed of both;

Speed defined as the rate at which an object covers distance.

$Speed = \frac{Distance}{Time}$

Mai traveled 15 meters in 6 seconds

then;

Speed = $\frac{15}{6} = 2.5 m/s$

Priya travels 22 meters in 10 second.

then;

Speed = $\frac{22}{10} = 2.2 m/s$

Reason: Mai traveled faster because she covered a greater distance in the same amount of time.

7 0

3 years ago

Let Q(x, y) be the predicate "If x < y then x2 < y2," with domain for both x and y being R, the set of all real numbers.

Levart [38]

Answer:

a) Q(-2,1) is false

b) Q(-5,2) is false

c)Q(3,8) is true

d)Q(9,10) is true

Step-by-step explanation:

Given data is $Q(x,y)$ is predicate that $x$ then $x^{2}$ . where $x,y$ are rational numbers.

a)

when $x=-2, y=1$

Here $-2$ that is $x$ satisfied. Then

$(-2)^{2}$

$4$ this is wrong. since $4>1$

That is $x^{2}$ $>y^{2}$ Thus $Q(x,y)$ $=Q(-2,1)$ is false.

b)

Assume $Q(x,y)=Q(-5,2)$ .

That is $x=-5, y=2$

Here $-5$ that is $x$ this condition is satisfied.

Then

$(-5)^{2}$

$25$ this is not true. since $25>4$ .

This is similar to the truth value of part (a).

Since in both $x$ satisfied and $x^{2} >y^{2}$ for both the points.

c)

if $Q(x,y)=Q(3,8)$ that is $x=3$ and $y=8$

Here $3$ this satisfies the condition $x$ .

Then $3^{2}$

$9$ This also satisfies the condition $x^{2}$ .

Hence $Q(3,8)$ exists and it is true.

d)

Assume $Q(x,y)=Q(9,10)$

Here $9$ satisfies the condition $x$

Then $9^{2}$

$81$ satisfies the condition $x^{2}$ .

Thus, $Q(9,10)$ point exists and it is true. This satisfies the same values as in part (c)

6 0

3 years ago

Solve for f. Show your work! 8=f-(13-2)

Nana76 [90]

Answer:

So F=19

Step-by-step explanation:

8=f-(13-2)

8=f-11

+11 +11 You plus 11 by both sides

19=f

You can check you answer by plugging it in

8=19-(13-2)

your answer would still be 19

8 0

3 years ago

Factor the polynomial below.<br> 9x squared minus 16y squared

GaryK [48]

9x^2-16y^2=
(3x+4y)(3x-4y)

7 0

3 years ago