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3 years ago

Is 4+(3×y) equivalent to (4+3)×y

Mathematics

1 answer:

Ivenika [448]3 years ago

8 0

Answer:

No they are not

Step-by-step explanation:

in the second expression

it would turn out to be

4^xy+3^xy

Which is way different then just

4+3^xy

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This shape is made up if the following

Alex

Answer:

a. 100.48

b. 1,004.8

c. 1,105.28

Step-by-step explanation:

a. a cone with volume = ⅓×3.14×4²×6=

100.48

b. a cylinder with volume = 3.14×4²×20=

1,004.8

c. total volume = 100.48+1,004.8

= 1,105.28

5 0

3 years ago

2. What are the next two terms of the following sequence?-2,4,-8, 16, ...

Marat540 [252]

Answer:

Step-by-step explanation:

$-2\\(-2)(-2)=4\\(-2)(4)=-8\\(-2)(-8)=16\\-----------------\\(-2)(16)=-32\\(-2)(-32)=64\\\vdots$

Each next term is created by multiplying the previous term by (-2).

3 0

3 years ago

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A basketball coach had 40 ounces of sunflower seeds . She wants to divide the seeds equally into 12 bags to give to her players

antoniya [11.8K]

40 divided by 12
Equals = 3.33333333

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3 years ago

Read 2 more answers

Scott and Letitia are brother and sister. After dinner, they have to do the dishes, with one washing and the other drying. They

ehidna [41]

Answer:

The probability that Scott will wash is 2.5

Step-by-step explanation:

Given

Let the events be: P = Purple and G = Green

$P = 2$

$G = 3$

Required

The probability of Scott washing the dishes

If Scott washes the dishes, then it means he picks two spoons of the same color handle.

So, we have to calculate the probability of picking the same handle. i.e.

$P(Same) = P(G_1\ and\ G_2) + P(P_1\ and\ P_2)$

This gives:

$P(G_1\ and\ G_2) = P(G_1) * P(G_2)$

$P(G_1\ and\ G_2) = \frac{n(G)}{Total} * \frac{n(G)-1}{Total - 1}$

$P(G_1\ and\ G_2) = \frac{3}{5} * \frac{3-1}{5- 1}$

$P(G_1\ and\ G_2) = \frac{3}{5} * \frac{2}{4}$

$P(G_1\ and\ G_2) = \frac{3}{10}$

$P(P_1\ and\ P_2) = P(P_1) * P(P_2)$

$P(P_1\ and\ P_2) = \frac{n(P)}{Total} * \frac{n(P)-1}{Total - 1}$

$P(P_1\ and\ P_2) = \frac{2}{5} * \frac{2-1}{5- 1}$

$P(P_1\ and\ P_2) = \frac{2}{5} * \frac{1}{4}$

$P(P_1\ and\ P_2) = \frac{1}{10}$

<em>Note that: 1 is subtracted because it is a probability without replacement</em>

So, we have:

$P(Same) = P(G_1\ and\ G_2) + P(P_1\ and\ P_2)$

$P(Same) = \frac{3}{10} + \frac{1}{10}$

$P(Same) = \frac{3+1}{10}$

$P(Same) = \frac{4}{10}$

$P(Same) = \frac{2}{5}$

8 0

3 years ago

Explain how opposites are applied when solving one-step equations. How do you know what to use to solve a one-step equation? Be

weeeeeb [17]

Input: 4y-16+8y=-4 answer: 12y-16=-4 HERE IS YOUR ANSWER

6 0

2 years ago