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garri49 [273]
3 years ago
9

Is 4+(3×y) equivalent to (4+3)×y

Mathematics
1 answer:
Ivenika [448]3 years ago
8 0

Answer:

No they are not

Step-by-step explanation:

in the second expression

it would turn out to be

4^xy+3^xy

Which is way different then just

4+3^xy

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Y-(-4)=-3[x-(2)] I'm looking for the slope intercept form of y
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Y+4=-3(x-2)
y+4=-3x+6
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A bike tire has a diameter of 16 inches What is the radius of the bike What is the circumference of the bike
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Matt has 36 cards<br> and Andy has 35 more cards<br> than Matt. How many cards does Andy have?
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5 0
2 years ago
Read 2 more answers
Anne is running on a trail at an average speed of 6 miles per hour beginning at mile marker 4. John is running on the trail at t
Sphinxa [80]

Answer:

John is running faster.

Step-by-step explanation:

Given that:

Average Speed of Anne = 6 miles per hour

Speed of John can be represented in the table below:

\begin{center}\begin{tabular}{ c c}Time (hours) x & Mile Marker y \\ 0 & 1  \\  0.5 & 4.5  \\   1 & 8  \\ 1.5 & 11.5  \\\end{tabular}\end{center}

To find:

Who is running faster of the both i.e. Anne and John?

Solution:

Here, to find the faster runner we can compare the average speed of both the runners.

We are given that, average speed of Anne = 6 miles per hour

We will have to calculate the average speed of John to find the faster runner.

<em>Average speed</em> can be calculated by dividing the total distance traveled with the total time taken.

Total distance traveled by John = 11.5 - 1 = 10.5 miles

Total time taken by John = 1.5 hours

Average speed of John = \frac{10.5}{1.5} = 7\ miles/hr

Clearly Average speed of John is greater than that of Anne's.

Therefore, <em>John runs faster</em>.

6 0
3 years ago
The probability of a customer arrival at a grocery service counter in any one second is equal to 0.3. Assume that customers arri
Svetllana [295]

Answer:

Step-by-step explanation:

Given that the probability of a customer arrival at a grocery service counter in any one second is equal to 0.3

Assume that customers arrive in a random stream, so an arrival in any one second is independent of all others.

i.e. X the no of customers arriving is binomial with p = 0.3 and q = 1-0.3 =0.7

a) the probability that the first arrival will occur during the third one-second interval.

= Prob that customer did not arrive in first 2 seconds * prob customer arrive in 3rd sec

= 0.7^2 (0.3)\\= 0.147

b)  the probability that the first arrival will not occur until at least the third one-second interval.

Prob that customer did not arrive in first two seconds *(Prob customer arrives in 3rd or 4th or 5th.....)

=(0.7^2)[0.3+0.7*0.3+0.7^2*0.3+....)\\

The term inside bracket is a geometric infinite progression with common ratio - 0.7 <1

Hence the series converges

Prob =0.7^2 *\frac{0.3}{1-0.7} \\=0.49

5 0
3 years ago
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