Answer:
1
Step-by-step explanation:
Numbers to the "right of 0" implies the positive numbers. And an integer has no fractional component. Thus, the first integer to the right of 0 would be 1.
Cheers.
Answer:
False
Step-by-step explanation:
÷6 = ×
Answer: C - fog(2) = 1
Step-by-step explanation: x^3 and x-1 make x
^3-3x^2+3x-1.
Make those into a root by factoring the x^3 and 3x^2+3x-1
Cannot be simplified anymore so (x-1)(x^2-2x+1)
x^2 can be simplifed to make (x-1)(x-1)
So, you get (x-1)(x-1)(x-1).
Answer can be simplified to x=1 or fog(2) = 1
Hope you have the answer you are looking for and have a nice day!
is undefined when the denominator is 0. i.e. x - 3 = 0 or x + 2 = 0 or x - 5 = 0 i.e. x = 3 or x = -2 or x = 5.
Hence, Bobby is right.
Answer:
The base is: ![3 \sqrt[3]{4}](https://tex.z-dn.net/?f=3%20%5Csqrt%5B3%5D%7B4%7D)
Step-by-step explanation:
Given
![f(x) = \frac{1}{4}(\sqrt[3]{108})^x](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7B1%7D%7B4%7D%28%5Csqrt%5B3%5D%7B108%7D%29%5Ex)
Required
The base
Expand 108
![f(x) = \frac{1}{4}(\sqrt[3]{3^3 * 4})^x](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7B1%7D%7B4%7D%28%5Csqrt%5B3%5D%7B3%5E3%20%2A%204%7D%29%5Ex)
Rewrite the exponent as:
Expand
Rewrite as:
![f(x) = \frac{1}{4}(3 \sqrt[3]{4})^x](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7B1%7D%7B4%7D%283%20%5Csqrt%5B3%5D%7B4%7D%29%5Ex)
An exponential function has the following form:
Where
By comparison:
![b =3 \sqrt[3]{4}](https://tex.z-dn.net/?f=b%20%3D3%20%5Csqrt%5B3%5D%7B4%7D)
So, the base is:
