Let the faculties be X and the number of students be Y.
X/Y = 17/3
3X= 17Y
X=17Y/3
Let that be equation 1
We also know that X+Y = 740. Let it be equation 2
Substitute equation 1 in equation 2
(17Y/3)+Y= 740
20Y/3 = 740
Y=111
Since the total is 740, then X equal 740-111 =629.
The number of faculties is 111 and the number of students is 629.
43-7= 36
Range is highest number minus smallest number
38 es par 35 es par eso es todo?
There are 2 ways to do this. I'm going to do it the way that I think is most simple.
You have to find their LCM which is 40. Now times 40 to 1/4 v and 7/10
The equation then becomes 10+40v=28
You simplify it: 40v=18
v= 9/20
Answer:
Option D, I agree with neither Elena nor Lin
Step-by-step explanation:
The remaining part of the question is attached herewith
Solution
As we can see in the image
ED is perpendicular to AB and BC is perpendicular to AB
Thus, as per the Pythagoras theorem,
AC^2 = AB^2 + BC^2
14^2 = 6^2 + BC^2
BC^2 = 196-36 = 160
BC = 12.649 OR 12.65
Hence, option D
I agree with neither Elena nor Lin
