Given :
As a plane takes off it ascends at a 20 degree angle of elevation.
If the plane has been travelling at an average rate of 290 ft/s and continues to ascend at the same angle.
To Find :
How high is the plane after 10 seconds.
Solution :
Distance travelled by plane, D = 2900 ft.
Angle of elevation, Ф = 20°.
Height gained is given by :

H = 2900 × sin 20°
H = 991.86 ft.
Therefore, height of plane after 10 seconds is 991.86 ft.
Hence, this is the required solution.
Answer:
C. y= 14x+20
Step-by-step explanation:
By looking at the table, you can put in the x-values into all of the equations until you find the corresponding y-values that matches with the values in the table. For example: y= 14(2)+ 20, y=48. y= 14(20) +20, y=300. Hope this helped!
Hello :
<span>a point on the y-axis is : P( 0, y)
</span>PA = PB or PA² = PB².... A(7, -7) B(1,1)
(7-0)²+(-7-y)² = (1-0)² + (1-y)²
49+49+14y+y² = 1+1-2y+y²
16y = - 96
y= - 6
Answer:
I can totally help you but, what is your number by chance?
Step-by-step explanation: